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The electrode potential for the given half cell reaction at pH = 5 will be - ____.
(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)
(answer upto 2 decimal places)
(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)
(answer upto 2 decimal places)
Correct answer is '0.93'. Can you explain this answer?
Most Upvoted Answer
The electrode potential for the given half cell reaction at pH = 5 wil...
As we know oxidation equals to standard oxidation minus 0.05 91 upon 4 log q and we can find lock you by writing the cell diagram into reaction form H2O h2o2 + 4 x + 4 electron it means that there is a transfer of electron so value of n become 4 noticing the equation we generaligible oxidation half cell here standard reduction potential is given so we put a minus sign in standard eduction potential to get standard oxidation potential so our required standard oxydation potential is -1.23 volt now apply nest equation applying this we get value of eoxidation that is 0.94 volt but in the question is asked that electrode potential so we put a negative sign on our required value of oxidation potential there for our required answer is - 0.94 volt
most of best friend get doubt that how PH in this question use as we knowing I need quicklybrium that concentration of h+ iron is equals to 10 to the power minus of PH now in the question pH is given that 5 so using this relation we get concentration of h+h+ ionic 10 to the power minus 5 thank you
most of best friend get doubt that how PH in this question use as we knowing I need quicklybrium that concentration of h+ iron is equals to 10 to the power minus of PH now in the question pH is given that 5 so using this relation we get concentration of h+h+ ionic 10 to the power minus 5 thank you
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The electrode potential for the given half cell reaction at pH = 5 wil...
The given half cell reaction is:
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The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer?
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The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer?.
The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer?.
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The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer?, a detailed solution for The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? has been provided alongside types of The electrode potential for the given half cell reaction at pH = 5 will be - ____.(R = 8.314 J mol–1 K–1; Temp. = 298 K; Oxygen under std. atm. pressure of 1 bar)(answer upto 2 decimal places)Correct answer is '0.93'. Can you explain this answer? theory, EduRev gives you an
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