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In an adjacency list representation of an undirected simple graph G = (V, E), each edge (u, v) has two adjacency list entries: [v] in the adjacency list of u, and [u] in the adjacency list of v. These are called twins of each other. A twin pointer is a pointer from an adjacency list entry to its twin. If |E| = m and |V | = n, and the memory size is not a constraint, what is the time complexity of the most efficient algorithm to set the twin pointer in each entry in each adjacency list?
  • a)
    Θ(n2)
  • b)
    Θ(m+n)
  • c)
    Θ(m2)
  • d)
    Θ(n4)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In an adjacency list representation of an undirected simple graph G = ...
First you need to find twins of each node. You can do this using level order traversal (i.e., BFS) once. Time complexity of BFS is Θ(m +n).
And you have to use linked list for representation which is extra space (but memory size is not a constraint here).
Final, time complexity is Θ(m + n) to set twin pointer.
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Community Answer
In an adjacency list representation of an undirected simple graph G = ...
First you need to find twins of each node. You can do this using level order traversal (i.e., BFS) once. Time complexity of BFS is Θ(m +n).
And you have to use linked list for representation which is extra space (but memory size is not a constraint here).
Final, time complexity is Θ(m + n) to set twin pointer.
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In an adjacency list representation of an undirected simple graph G = (V, E), each edge (u, v) has two adjacency list entries: [v] in the adjacency list of u, and [u] in the adjacency list of v. These are called twins of each other. A twin pointer is a pointer from an adjacency list entry to its twin. If |E| = m and |V | = n, and the memory size is not a constraint, what is the time complexity of the most efficient algorithm to set the twin pointer in each entry in each adjacency list?a)Θ(n2)b)Θ(m+n)c)Θ(m2)d)Θ(n4)Correct answer is option 'B'. Can you explain this answer?
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In an adjacency list representation of an undirected simple graph G = (V, E), each edge (u, v) has two adjacency list entries: [v] in the adjacency list of u, and [u] in the adjacency list of v. These are called twins of each other. A twin pointer is a pointer from an adjacency list entry to its twin. If |E| = m and |V | = n, and the memory size is not a constraint, what is the time complexity of the most efficient algorithm to set the twin pointer in each entry in each adjacency list?a)Θ(n2)b)Θ(m+n)c)Θ(m2)d)Θ(n4)Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about In an adjacency list representation of an undirected simple graph G = (V, E), each edge (u, v) has two adjacency list entries: [v] in the adjacency list of u, and [u] in the adjacency list of v. These are called twins of each other. A twin pointer is a pointer from an adjacency list entry to its twin. If |E| = m and |V | = n, and the memory size is not a constraint, what is the time complexity of the most efficient algorithm to set the twin pointer in each entry in each adjacency list?a)Θ(n2)b)Θ(m+n)c)Θ(m2)d)Θ(n4)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an adjacency list representation of an undirected simple graph G = (V, E), each edge (u, v) has two adjacency list entries: [v] in the adjacency list of u, and [u] in the adjacency list of v. These are called twins of each other. A twin pointer is a pointer from an adjacency list entry to its twin. If |E| = m and |V | = n, and the memory size is not a constraint, what is the time complexity of the most efficient algorithm to set the twin pointer in each entry in each adjacency list?a)Θ(n2)b)Θ(m+n)c)Θ(m2)d)Θ(n4)Correct answer is option 'B'. Can you explain this answer?.
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