Consider a complete binary tree with 7 nodes. Let A denote the set of ...
The value of A, the set of first 3 elements obtained by performing Breadth-First Search (BFS) starting from the root, would depend on the specific arrangement of the nodes in the complete binary tree.
Breadth-First Search (BFS) visits all the nodes at the same depth level before moving on to the next depth level. In a complete binary tree with 7 nodes, the root will be at level 0, its children will be at level 1, and their children will be at level 2.
To perform BFS, we start at the root and visit its children first, from left to right. Then, we move on to the next depth level and visit the children of the nodes at that level, again from left to right.
So, the value of A will depend on the specific arrangement of the nodes in the tree. Without knowing the arrangement of the nodes, it's not possible to determine the exact elements in set A.
Similarly, the value of B, the set of first 3 elements obtained by performing Depth-First Search (DFS) starting from the root, would also depend on the specific arrangement of the nodes in the complete binary tree.
Depth-First Search (DFS) explores as far as possible along each branch before backtracking. In a complete binary tree with 7 nodes, DFS can start from the root and explore the left branch first, then backtrack and explore the right branch.
Again, without knowing the arrangement of the nodes, it's not possible to determine the exact elements in set B.
In summary, the values of sets A and B would depend on the arrangement of the nodes in the complete binary tree and cannot be determined without that information.
Consider a complete binary tree with 7 nodes. Let A denote the set of ...
In case of BFS if we draw complete binary tree then in Set A we have level1+level2.
In DFS we have level1+ level 2 + level 3.
So A-B= remaining element of level 2.
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