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The bending force required for a 1.5 mm thick steel (having ultimate tensile strength 800 MPa) sheet of 1 m length to be bent in a wiping die (K = 0.33) (in kN) is . The die radius used is 3 mm by using the governing equation = bending force, Fb=kLσt2/W. Every symbol has their using meaning.Correct answer is '79.2'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The bending force required for a 1.5 mm thick steel (having ultimate tensile strength 800 MPa) sheet of 1 m length to be bent in a wiping die (K = 0.33) (in kN) is . The die radius used is 3 mm by using the governing equation = bending force, Fb=kLσt2/W. Every symbol has their using meaning.Correct answer is '79.2'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The bending force required for a 1.5 mm thick steel (having ultimate tensile strength 800 MPa) sheet of 1 m length to be bent in a wiping die (K = 0.33) (in kN) is . The die radius used is 3 mm by using the governing equation = bending force, Fb=kLσt2/W. Every symbol has their using meaning.Correct answer is '79.2'. Can you explain this answer?.

Solutions for The bending force required for a 1.5 mm thick steel (having ultimate tensile strength 800 MPa) sheet of 1 m length to be bent in a wiping die (K = 0.33) (in kN) is . The die radius used is 3 mm by using the governing equation = bending force, Fb=kLσt2/W. Every symbol has their using meaning.Correct answer is '79.2'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

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