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In a U tube manometer filled with mercury and measuring the pressure of air in a container, the difference in height of the two columns is 12 cm. If the specific weight of mercury is 13.6 kg/liter, then what is the pressure measured by the manometer? (g = 10 m/sec2)
  • a)
    0.1512 bar
  • b)
    0.1632 bar
  • c)
    16320 bar
  • d)
    0.1005 bar
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a U tube manometer filled with mercury and measuring the pressure o...
To find the pressure measured by the manometer, we need to first determine the pressure difference between the two columns of mercury in the manometer.

Given:
Difference in height of the two columns = 12 cm
Specific weight of mercury = 13.6 kg/liter
Acceleration due to gravity (g) = 10 m/s²

Let's calculate the pressure difference step by step:

1. Convert the specific weight of mercury from kg/liter to N/m³:
Specific weight = density x acceleration due to gravity
Since the density of mercury is approximately 13.6 kg/liter, we can convert it to N/m³ as follows:
Specific weight = 13.6 kg/liter x 1000 liter/m³ x 10 m/s²
Specific weight = 136,000 N/m³

2. Convert the height difference from cm to meters:
Height difference = 12 cm = 0.12 m

3. Calculate the pressure difference using the formula:
Pressure difference = specific weight x height difference
Pressure difference = 136,000 N/m³ x 0.12 m
Pressure difference = 16,320 N/m²

4. Convert the pressure from N/m² to bar:
1 bar = 100,000 N/m²
Pressure difference in bar = 16,320 N/m² / 100,000 N/m²
Pressure difference in bar = 0.1632 bar

Therefore, the pressure measured by the manometer is 0.1632 bar. Hence, option B is the correct answer.
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Community Answer
In a U tube manometer filled with mercury and measuring the pressure o...
Concept:
Pressure intensity at any point in a fluid, P = ρ×g×h
Where,
ρ = mass density of fluid which is assumed to be constant along with the depth, g = acceleration due to gravity, h = height of fluid measured from the free surface.
1 litre = 10-3 m3
1 bar = 105 pascal
Calculation:
Given:

S = 13.6 kg/liter, ρ = 13.6 × 10kg/m3, h = 12 cm = 0.12 m
P = ρ×g×h = 13600 × 0.12 × 10 = 16320 pascal = 0.1632 bar
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In a U tube manometer filled with mercury and measuring the pressure of air in a container, the difference in height of the two columns is 12 cm. If the specific weight of mercury is 13.6 kg/liter, then what is the pressure measured by the manometer? (g = 10 m/sec2)a)0.1512 barb)0.1632 barc)16320 bard)0.1005 barCorrect answer is option 'B'. Can you explain this answer?
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