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Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Select the correct order of initials T (True) and F (False) for the following statements:(I) Co(II) is stablised in the presence of strong field ligands, while Co(III) is stablised in the presence of weak field ligands.(II) [Cr(NH3)6]3+ is an inner orbital complex with crystal field stablisation energy equal to -1.2Δo.(III) In [CoF6]3-, F- is a weak field ligand so that Δo (IV) Crystal field splitting in ferrocyanide ion is greater than that in ferricyanide ion.a)T, F, T, Fb)F, T, F, Fc)F, T, T, Td)T, T, F, TCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.