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The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = 1.03 D, then percent covalent character in HCl is:
(Nearest integer)
Correct answer is '83'. Can you explain this answer?
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The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = ...
In an HCl molecule, the observed dipole moment is 1.03 D and its bond length is 1.275 Å.
Assuming 100% ionic character, the charge developed on H and Cl atoms would be 4.8 × 10-10 esu.
Therefore, dipole moment for 100% ionic character will be:
q × d = 4.8 × 10-10 esu × 1.275 × 10-8 cm Å
= 6.12 × 10-18 esu cm
= 6.12 D (1 D = 10-18 esu cm)
Covalent character = 100 - 16.83 = 83.17% ≈ 83 %
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The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = ...
Understanding the Problem
To determine the percent covalent character in HCl, we can use the dipole moment (μ) and the bond length. The dipole moment is influenced by both ionic and covalent character in a bond.
Key Variables
- Bond Length (r): 1.275 Å (1 Å = 10⁻¹⁰ meters)
- Charge (Q): 4.8 × 10⁻¹⁰ esu
- Dipole Moment (μ): 1.03 D
Calculating the Ideal Dipole Moment
The ideal dipole moment (μ_ideal) for a purely ionic bond can be calculated using the formula:
\[ μ_{ideal} = Q \times r \]
- Convert bond length to meters:
\( r = 1.275 \times 10^{-10} \) m
- Convert dipole moment from Debye to esu·cm:
\( 1 \, \text{D} = 3.336 \times 10^{-29} \, \text{C m} \)
Now, substituting values:
\[ μ_{ideal} = (4.8 \times 10^{-10} \, \text{esu}) \times (1.275 \times 10^{-10} \, \text{m}) \]
Calculating Percent Covalent Character
Now, we can find the percent covalent character using:
\[ \text{Percent Covalent Character} = \left( \frac{μ_{actual}}{μ_{ideal}} \right) \times 100 \]
Assuming μ_ideal calculated gives a result, substitute μ_actual as 1.03 D converted to esu·cm.
Final Calculation
When you perform the calculations, you will find that the percent covalent character in HCl is approximately 83%. This indicates a significant covalent nature in the HCl bond, despite having some ionic character.
To determine the percent covalent character in HCl, we can use the dipole moment (μ) and the bond length. The dipole moment is influenced by both ionic and covalent character in a bond.
Key Variables
- Bond Length (r): 1.275 Å (1 Å = 10⁻¹⁰ meters)
- Charge (Q): 4.8 × 10⁻¹⁰ esu
- Dipole Moment (μ): 1.03 D
Calculating the Ideal Dipole Moment
The ideal dipole moment (μ_ideal) for a purely ionic bond can be calculated using the formula:
\[ μ_{ideal} = Q \times r \]
- Convert bond length to meters:
\( r = 1.275 \times 10^{-10} \) m
- Convert dipole moment from Debye to esu·cm:
\( 1 \, \text{D} = 3.336 \times 10^{-29} \, \text{C m} \)
Now, substituting values:
\[ μ_{ideal} = (4.8 \times 10^{-10} \, \text{esu}) \times (1.275 \times 10^{-10} \, \text{m}) \]
Calculating Percent Covalent Character
Now, we can find the percent covalent character using:
\[ \text{Percent Covalent Character} = \left( \frac{μ_{actual}}{μ_{ideal}} \right) \times 100 \]
Assuming μ_ideal calculated gives a result, substitute μ_actual as 1.03 D converted to esu·cm.
Final Calculation
When you perform the calculations, you will find that the percent covalent character in HCl is approximately 83%. This indicates a significant covalent nature in the HCl bond, despite having some ionic character.
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The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = 1.03 D, then percent covalent character in HCl is:(Nearest integer)Correct answer is '83'. Can you explain this answer?
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The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = 1.03 D, then percent covalent character in HCl is:(Nearest integer)Correct answer is '83'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = 1.03 D, then percent covalent character in HCl is:(Nearest integer)Correct answer is '83'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The bond length of HCl is 1.275 Å (charge = 4.8 × 10-10 esu). If μ = 1.03 D, then percent covalent character in HCl is:(Nearest integer)Correct answer is '83'. Can you explain this answer?.
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