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What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)
(pKa of CH3COOH = 4.5)
Correct answer is '1'. Can you explain this answer?
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What should be the molarity of the solution of sodium acetate to be a...
The solution formed will be an acidic buffer.
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Calculating the Molarity of Sodium Acetate Solution
To achieve a solution with a pH of 5.5 by mixing a 0.1 M solution of acetic acid (CH3COOH) with sodium acetate (CH3COONa), we need to consider the equilibrium between CH3COOH and CH3COO- ions.
Step 1: Writing the Equilibrium Equation
CH3COOH + H2O ⇌ CH3COO- + H3O+
Since the pH is 5.5, we can calculate the concentration of H3O+ ions using the formula pH = -log[H3O+].
Step 2: Calculating [H3O+]
pH = 5.5
[H3O+] = 10^(-5.5) = 3.16 x 10^(-6) M
Step 3: Using the Henderson-Hasselbalch equation
pH = pKa + log([A-]/[HA])
5.5 = 4.5 + log([CH3COO-]/[CH3COOH])
1 = log([CH3COO-]/[CH3COOH])
[CH3COO-]/[CH3COOH] = 10
Step 4: Mole Ratio
Since the mole ratio of CH3COOH to CH3COO- is 1:1, the concentration of CH3COO- must be equal to the concentration of CH3COOH.
Step 5: Total Concentration of Acetic Acid
Total concentration of acetic acid = 0.1 M (initial concentration of CH3COOH) + x M (concentration of CH3COONa)
Step 6: Solving for x
0.1 + x = 10
x = 9.9 M
Therefore, the molarity of the sodium acetate solution to be added to the 0.1 M solution of acetic acid is approximately 10 M, which is rounded to the nearest integer as 1 M.
To achieve a solution with a pH of 5.5 by mixing a 0.1 M solution of acetic acid (CH3COOH) with sodium acetate (CH3COONa), we need to consider the equilibrium between CH3COOH and CH3COO- ions.
Step 1: Writing the Equilibrium Equation
CH3COOH + H2O ⇌ CH3COO- + H3O+
Since the pH is 5.5, we can calculate the concentration of H3O+ ions using the formula pH = -log[H3O+].
Step 2: Calculating [H3O+]
pH = 5.5
[H3O+] = 10^(-5.5) = 3.16 x 10^(-6) M
Step 3: Using the Henderson-Hasselbalch equation
pH = pKa + log([A-]/[HA])
5.5 = 4.5 + log([CH3COO-]/[CH3COOH])
1 = log([CH3COO-]/[CH3COOH])
[CH3COO-]/[CH3COOH] = 10
Step 4: Mole Ratio
Since the mole ratio of CH3COOH to CH3COO- is 1:1, the concentration of CH3COO- must be equal to the concentration of CH3COOH.
Step 5: Total Concentration of Acetic Acid
Total concentration of acetic acid = 0.1 M (initial concentration of CH3COOH) + x M (concentration of CH3COONa)
Step 6: Solving for x
0.1 + x = 10
x = 9.9 M
Therefore, the molarity of the sodium acetate solution to be added to the 0.1 M solution of acetic acid is approximately 10 M, which is rounded to the nearest integer as 1 M.
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What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer?
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What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer?.
What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What should be the molarity of the solution of sodium acetate to be added to a 0.1 M solution of CH3COOH to give a solution of pH = 5.5? (Nearest integer)(pKa of CH3COOH = 4.5)Correct answer is '1'. Can you explain this answer?.
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