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Let e and f be events of sample space s of an experiment,then p(e / f) +p(ē /f) is?
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Let e and f be events of sample space s of an experiment,then p(e / f)...
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Definition

In probability theory, conditional probability is the probability of an event occurring given that another event has occurred. It is denoted as P(A/B), which means the probability of A happening given that B has already happened.

The complement of an event E is the event that E does not occur. It is denoted as E'.


Explanation

The probability of event E given that event F has already occurred is denoted as P(E/F). Similarly, the probability of the complement of event E given that event F has already occurred is denoted as P(E'/F).

Now, we know that the total probability of an event is equal to 1. Therefore, we can write:



  • P(E) + P(E') = 1

  • P(E/F) + P(E'/F) = 1



Subtracting the second equation from the first, we get:



  • P(E) - P(E/F) = P(E') - P(E'/F)



Adding and subtracting P(E' ∩ F) on both sides, we get:



  • P(E ∩ F) - P(E/F) = P(E' ∩ F) - P(E'/F)

  • P(E/F) - P(E' ∩ F) = P(E'/F) - P(E ∩ F)



Now, using the definition of conditional probability, we can write:



  • P(E ∩ F) = P(F) × P(E/F)

  • P(E' ∩ F) = P(F) × P(E'/F)



Substituting these values in the above equation, we get:



  • P(F) × (P(E/F) - P(E'/F)) = P(F) × (P(E'/F) - P(E ∩ F))

  • P(E/F) - P(E'/F) = P(E'/F) - P(E ∩ F)



Therefore, we can conclude that:



  • P(E/F) - P(E'/F) = P(E'/F) - P(E ∩ F)

  • P(E/F) + P(E'/F) = P(E ∩ F) + P(E'/F)



Hence, we can say that the probability of event E given that event F has occurred plus the probability of the complement of event E given that event F has occurred is equal to the sum of the probabilities of the intersection of events E and F with the complement of event E given that event F has occurred and the intersection of events E' and F given that event E has occurred.
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Let e and f be events of sample space s of an experiment,then p(e / f)...
P(e/f)
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Let e and f be events of sample space s of an experiment,then p(e / f) +p(ē /f) is?
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