The first number is 104 which is divisible by 13.

To find the sum of all natural numbers between 100 and 400 that are divisible by 13, we need to follow these steps:

1. Identify the first and last terms of the series:
- The first term of the series is the smallest multiple of 13 that is greater than or equal to 100. To find this, we can divide 100 by 13 and round up to the nearest integer: 100 ÷ 13 = 7.69, rounded up to 8. So, the first term is 8 * 13 = 104.
- The last term of the series is the largest multiple of 13 that is less than or equal to 400. To find this, we can divide 400 by 13 and round down to the nearest integer: 400 ÷ 13 = 30.77, rounded down to 30. So, the last term is 30 * 13 = 390.

2. Calculate the number of terms in the series:
- To find the number of terms in the series, we can use the formula: Number of terms = (last term - first term) ÷ common difference + 1.
- In this case, the common difference is 13. So, the number of terms = (390 - 104) ÷ 13 + 1 = 286 ÷ 13 + 1 = 22 + 1 = 23.

3. Calculate the sum of the series:
- To find the sum of a series, we can use the formula: Sum = (number of terms / 2) * (first term + last term).
- In this case, the sum = (23 / 2) * (104 + 390) = 11.5 * 494 = 5683.

Therefore, the sum of all natural numbers between 100 and 400 that are divisible by 13 is 5683. However, none of the given options match the calculated answer. There may be an error in the options provided.