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A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?
- a)CL
- b)CH
- c)CL-ML
- d)CI
Correct answer is option 'B'. Can you explain this answer?
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A fine grained soil has liquid limit of 60 and plastic limit of 20 as ...
Classification of Fine Grained Soil
To classify a fine grained soil according to the Indian Standard (IS) classification system, we need to determine its liquid limit (LL) and plastic limit (PL) values from laboratory tests. Based on these values, the soil is represented by a letter symbol.
Given Data:
- Liquid Limit (LL) = 60
- Plastic Limit (PL) = 20
Determination of Plasticity Index (PI)
The plasticity index (PI) is the numerical difference between the liquid limit and the plastic limit of the soil.
PI = LL - PL
= 60 - 20
= 40
Classification of Fine Grained Soil
The classification of fine grained soil is based on its plasticity index and the plasticity chart provided in the Indian Standard (IS) code.
Step 1: Determine the Group Index (GI)
The group index (GI) can be determined using the plasticity index (PI) as follows:
- For PI < 7,="" gi="PI" +="" />
- For PI ≥ 7, GI = PI + 0.5
In this case, since PI = 40, which is greater than 7, we use the second equation:
GI = 40 + 0.5
= 40.5
Step 2: Determine the Group Symbol
The group symbol is determined based on the group index (GI) as follows:
- For GI ≤ 4, the group symbol is "GW"
- For GI > 4 and GI ≤ 7, the group symbol is "GP"
- For GI > 7 and GI ≤ 15, the group symbol is "GC"
- For GI > 15 and GI ≤ 35, the group symbol is "GM"
- For GI > 35, the group symbol is "GC"
In this case, since GI = 40.5, which is greater than 35, the group symbol is "GC".
Step 3: Determine the Subgroup Symbol
The subgroup symbol is determined based on the plasticity index (PI) as follows:
- For PI < 4,="" the="" subgroup="" symbol="" is="" />
- For PI ≥ 4 and PI ≤ 7, the subgroup symbol is "I"
- For PI > 7 and PI ≤ 15, the subgroup symbol is "H"
- For PI > 15, the subgroup symbol is "P"
In this case, since PI = 40, which is greater than 15, the subgroup symbol is "P".
Final Classification Symbol
The final classification symbol is obtained by combining the group symbol and the subgroup symbol. In this case, the soil is represented by the letter symbol "CH" (Group GC, Subgroup P).
Hence, the correct answer is option B) CH.
To classify a fine grained soil according to the Indian Standard (IS) classification system, we need to determine its liquid limit (LL) and plastic limit (PL) values from laboratory tests. Based on these values, the soil is represented by a letter symbol.
Given Data:
- Liquid Limit (LL) = 60
- Plastic Limit (PL) = 20
Determination of Plasticity Index (PI)
The plasticity index (PI) is the numerical difference between the liquid limit and the plastic limit of the soil.
PI = LL - PL
= 60 - 20
= 40
Classification of Fine Grained Soil
The classification of fine grained soil is based on its plasticity index and the plasticity chart provided in the Indian Standard (IS) code.
Step 1: Determine the Group Index (GI)
The group index (GI) can be determined using the plasticity index (PI) as follows:
- For PI < 7,="" gi="PI" +="" />
- For PI ≥ 7, GI = PI + 0.5
In this case, since PI = 40, which is greater than 7, we use the second equation:
GI = 40 + 0.5
= 40.5
Step 2: Determine the Group Symbol
The group symbol is determined based on the group index (GI) as follows:
- For GI ≤ 4, the group symbol is "GW"
- For GI > 4 and GI ≤ 7, the group symbol is "GP"
- For GI > 7 and GI ≤ 15, the group symbol is "GC"
- For GI > 15 and GI ≤ 35, the group symbol is "GM"
- For GI > 35, the group symbol is "GC"
In this case, since GI = 40.5, which is greater than 35, the group symbol is "GC".
Step 3: Determine the Subgroup Symbol
The subgroup symbol is determined based on the plasticity index (PI) as follows:
- For PI < 4,="" the="" subgroup="" symbol="" is="" />
- For PI ≥ 4 and PI ≤ 7, the subgroup symbol is "I"
- For PI > 7 and PI ≤ 15, the subgroup symbol is "H"
- For PI > 15, the subgroup symbol is "P"
In this case, since PI = 40, which is greater than 15, the subgroup symbol is "P".
Final Classification Symbol
The final classification symbol is obtained by combining the group symbol and the subgroup symbol. In this case, the soil is represented by the letter symbol "CH" (Group GC, Subgroup P).
Hence, the correct answer is option B) CH.
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Community Answer
A fine grained soil has liquid limit of 60 and plastic limit of 20 as ...
Concept:
- Plasticity index of soil, Ip = WL - Wp
- Plasticity index of A-line, Ip = 0.73 (WL - 20)
Calculation:
Given,
liquid limit (WL) = 60%
plastic limit (Wp) = 20%
Ip of soil = WL - Wp = 60 - 20 = 40%
Ip of A-line = 0.73 (WL - 20) = 0.73 (60 - 20) = 29.2%
Ip of soil > Ip of A-line, So it will lie above A-line
and also WL > 50%, so soil is CH
Given,
liquid limit (WL) = 60%
plastic limit (Wp) = 20%
Ip of soil = WL - Wp = 60 - 20 = 40%
Ip of A-line = 0.73 (WL - 20) = 0.73 (60 - 20) = 29.2%
Ip of soil > Ip of A-line, So it will lie above A-line
and also WL > 50%, so soil is CH
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A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer?
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A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer?.
A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fine grained soil has liquid limit of 60 and plastic limit of 20 as per plasticity chart. According to IS classification, the soil is represented by which of the following letter symbols?a)CLb)CHc)CL-MLd)CICorrect answer is option 'B'. Can you explain this answer?.
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