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The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n is
Correct answer is '5100'. Can you explain this answer?
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The apparent depth of needle lying at the bottom of the tank which is ...
Actual depth of the needle in water,
h1 = 15.5 cm
Apparent depth, H = 15.5/1.94 = 7.99 cm
Here, H is less than h2. Thus to focus the needle again, the microscope should be moved up by the distance 8.5 − 7.99 = 0.51 cm
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The apparent depth of needle lying at the bottom of the tank which is ...
The apparent depth of an object submerged in a liquid can be calculated using the formula:
Apparent depth = Actual depth / Refractive index of the liquid
In this case, the actual depth of the needle is 15.5 cm and the refractive index of water is 1.00. So, the apparent depth of the needle in water is:
Apparent depth in water = 15.5 cm / 1.00 = 15.5 cm
According to the problem, the apparent depth of the needle when the liquid with refractive index 1.94 is used is 8.5 cm. So, we can use the same formula to find the actual depth of the needle in the liquid:
8.5 cm = Actual depth in the liquid / 1.94
Simplifying the equation, we get:
Actual depth in the liquid = 8.5 cm * 1.94 = 16.49 cm
To establish the focus on the needle again, the microscope needs to be moved by the displacement equal to the difference between the initial and final actual depths of the needle:
Displacement = Initial actual depth - Final actual depth
Displacement = 15.5 cm - 16.49 cm
Displacement = -0.99 cm
Therefore, the displacement of the microscope needed to establish the focus on the needle again is -0.99 cm.
Apparent depth = Actual depth / Refractive index of the liquid
In this case, the actual depth of the needle is 15.5 cm and the refractive index of water is 1.00. So, the apparent depth of the needle in water is:
Apparent depth in water = 15.5 cm / 1.00 = 15.5 cm
According to the problem, the apparent depth of the needle when the liquid with refractive index 1.94 is used is 8.5 cm. So, we can use the same formula to find the actual depth of the needle in the liquid:
8.5 cm = Actual depth in the liquid / 1.94
Simplifying the equation, we get:
Actual depth in the liquid = 8.5 cm * 1.94 = 16.49 cm
To establish the focus on the needle again, the microscope needs to be moved by the displacement equal to the difference between the initial and final actual depths of the needle:
Displacement = Initial actual depth - Final actual depth
Displacement = 15.5 cm - 16.49 cm
Displacement = -0.99 cm
Therefore, the displacement of the microscope needed to establish the focus on the needle again is -0.99 cm.
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The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer?
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The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer?.
The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The apparent depth of needle lying at the bottom of the tank which is filled with water to a height of 15.5 cm is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 to the same height as earlier, then the displacement of the microscope needed to establish the focus on the needle again is n μmn μm. The value of n isCorrect answer is '5100'. Can you explain this answer?.
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