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Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?
- a)Ethanal
- b)Ethanol
- c)Propyl amine
- d)Acetic acid
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Compound 'A', on heating with ammonia, gives compound 'B' which on tr...
Compound 'A' is acetic acid (option D).
Explanation:
1. Reaction of Compound 'A' with Ammonia:
When compound 'A', which is acetic acid (CH3COOH), is heated with ammonia (NH3), it undergoes a reaction to form compound 'B', which is ammonium acetate (CH3COONH4).
CH3COOH + NH3 → CH3COONH4
2. Reaction of Compound 'B' with Concentrated Sulfuric Acid:
Compound 'B' (ammonium acetate) is treated with concentrated sulfuric acid (H2SO4). This reaction results in the formation of compound 'C', which is ethyl acetate (CH3COOC2H5) and water (H2O).
CH3COONH4 + H2SO4 → CH3COOC2H5 + H2O
3. Reduction of Compound 'C' to Ethylamine:
Finally, compound 'C' (ethyl acetate) is reduced to ethylamine (C2H5NH2). The reduction can be carried out using a reducing agent such as lithium aluminum hydride (LiAlH4) or sodium borohydride (NaBH4).
CH3COOC2H5 + 2H2 → C2H5NH2 + CH3COOH
Therefore, the compound 'A' which, on heating with ammonia and treating with concentrated sulfuric acid, gives ethylamine upon reduction is acetic acid (CH3COOH).
Explanation:
1. Reaction of Compound 'A' with Ammonia:
When compound 'A', which is acetic acid (CH3COOH), is heated with ammonia (NH3), it undergoes a reaction to form compound 'B', which is ammonium acetate (CH3COONH4).
CH3COOH + NH3 → CH3COONH4
2. Reaction of Compound 'B' with Concentrated Sulfuric Acid:
Compound 'B' (ammonium acetate) is treated with concentrated sulfuric acid (H2SO4). This reaction results in the formation of compound 'C', which is ethyl acetate (CH3COOC2H5) and water (H2O).
CH3COONH4 + H2SO4 → CH3COOC2H5 + H2O
3. Reduction of Compound 'C' to Ethylamine:
Finally, compound 'C' (ethyl acetate) is reduced to ethylamine (C2H5NH2). The reduction can be carried out using a reducing agent such as lithium aluminum hydride (LiAlH4) or sodium borohydride (NaBH4).
CH3COOC2H5 + 2H2 → C2H5NH2 + CH3COOH
Therefore, the compound 'A' which, on heating with ammonia and treating with concentrated sulfuric acid, gives ethylamine upon reduction is acetic acid (CH3COOH).
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Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?a)Ethanalb)Ethanolc)Propyl amined)Acetic acidCorrect answer is option 'D'. Can you explain this answer?
Question Description
Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?a)Ethanalb)Ethanolc)Propyl amined)Acetic acidCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?a)Ethanalb)Ethanolc)Propyl amined)Acetic acidCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?a)Ethanalb)Ethanolc)Propyl amined)Acetic acidCorrect answer is option 'D'. Can you explain this answer?.
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Solutions for Compound 'A', on heating with ammonia, gives compound 'B' which on treating with conc. H2SO4 gives compound 'C'. This compound 'C' on reduction gives ethyl amine. What is compound 'A'?a)Ethanalb)Ethanolc)Propyl amined)Acetic acidCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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