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A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling, but he uses 900 gm weight instead of 1 kg. Also at the time of buying he uses 1100 gm instead of 1 kg. Find his overall profit percentage.
  • a)
    28.2%
  • b)
    52.3%
  • c)
    34.4%
  • d)
    39.6%
  • e)
    42.8%
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A shopkeeper markup his goods 25% above the cost price and gives 12% ...
Given
A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling.
He uses 900 gm weight instead of 1 kg.
Let cost of 1000 gm = Rs. 1000
Now,
C.P. of 1100 gm = Rs. 1000 ----(1)
C.P. = Rs. 1000
M.P. = Rs. 1250
Discount = 12%
S.P. = Rs. 1100
S.P. of 900 gm = Rs. 1100 ----(2)
To make quantities equal in equation (1) and (2),
Equation (1) Multiply by 9 and Equation (2) Multiply by 11
⇒ Actual C.P. = Rs. 1000 × 9 = Rs. 9000
Actual S.P. = Rs. 1100 × 11 = Rs. 12100
⇒ Profit = 12100 - 9000 = 3100
Profit percentage = 3100 × 100/9000 = 34.4%
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Community Answer
A shopkeeper markup his goods 25% above the cost price and gives 12% ...
Given data:
- Shopkeeper marks up his goods by 25% above the cost price.
- Shopkeeper gives a 12% discount to customers at the time of selling.
- Shopkeeper uses 900 gm weight instead of 1 kg while selling.
- Shopkeeper uses 1100 gm weight instead of 1 kg while buying.

Calculating the selling price:
Let's assume the cost price of the goods is 100.
Markup price = Cost price + 25% of cost price = 100 + (25/100) * 100 = 125

Calculating the weight at the time of selling:
If the goods weigh 900 gm instead of 1 kg, then the effective selling price per kg would be:
Selling price per kg = (125 * 1000) / 900 = 138.89

Calculating the effective selling price:
If the shopkeeper gives a 12% discount at the time of selling, then the effective selling price would be:
Effective selling price = 138.89 - (12/100) * 138.89 = 122.22

Calculating the buying price:
If the goods weigh 1100 gm instead of 1 kg, then the effective buying price per kg would be:
Buying price per kg = (100 * 1000) / 1100 = 90.91

Calculating the profit percentage:
Profit percentage = ((Selling price - Buying price) / Buying price) * 100
Profit percentage = ((122.22 - 90.91) / 90.91) * 100 = 34.4%

Therefore, the overall profit percentage is 34.4% (option C).
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A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling, but he uses 900 gm weight instead of 1 kg. Also at the time of buying he uses 1100 gm instead of 1 kg. Find his overall profit percentage.a)28.2%b)52.3%c)34.4%d)39.6%e)42.8%Correct answer is option 'C'. Can you explain this answer?
Question Description
A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling, but he uses 900 gm weight instead of 1 kg. Also at the time of buying he uses 1100 gm instead of 1 kg. Find his overall profit percentage.a)28.2%b)52.3%c)34.4%d)39.6%e)42.8%Correct answer is option 'C'. Can you explain this answer? for Banking Exams 2024 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling, but he uses 900 gm weight instead of 1 kg. Also at the time of buying he uses 1100 gm instead of 1 kg. Find his overall profit percentage.a)28.2%b)52.3%c)34.4%d)39.6%e)42.8%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Banking Exams 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shopkeeper markup his goods 25% above the cost price and gives 12% discount to customer at the time of selling, but he uses 900 gm weight instead of 1 kg. Also at the time of buying he uses 1100 gm instead of 1 kg. Find his overall profit percentage.a)28.2%b)52.3%c)34.4%d)39.6%e)42.8%Correct answer is option 'C'. Can you explain this answer?.
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