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One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ. The final temperature of the gas is equal to[Cv = 20 JK-1mol-1]a)75 Kb)150 Kc)225 kd)300 KCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ. The final temperature of the gas is equal to[Cv = 20 JK-1mol-1]a)75 Kb)150 Kc)225 kd)300 KCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. The work done is 3 kJ. The final temperature of the gas is equal to[Cv = 20 JK-1mol-1]a)75 Kb)150 Kc)225 kd)300 KCorrect answer is option 'B'. Can you explain this answer?.

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