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Trains A and B start traveling at the same time towards each other with constant speeds from stations X and Y, respectively. Train A reaches station Y in 10 minutes while train B takes 9 minutes to reach station X after meeting train A. Then the total time taken, in minutes, by train B to travel from station Y to station X is
  • a)
    6
  • b)
    10
  • c)
    15
  • d)
    12
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Trains A and B start traveling at the same time towards each other wit...
Given information:

- Train A and Train B start traveling towards each other simultaneously from stations X and Y, respectively.
- Train A reaches station Y in 10 minutes.
- Train B takes 9 minutes to reach station X after meeting Train A.

To find: Total time taken by Train B to travel from station Y to station X.

Approach:

Let's assume the distance between stations X and Y as 'd' and the speeds of Train A and Train B as 'vA' and 'vB', respectively.

Using the formula, speed = distance/time, we can write:

- vA = d/10 (Train A reaches station Y in 10 minutes)
- vB = d/tB (where tB is the time taken by Train B to travel from station Y to station X)

When Train A and Train B meet, the distance covered by both trains is equal to the distance between the two stations, i.e., d.

Using the formula, distance = speed × time, we can write:

- Distance covered by Train A in 9 minutes (before meeting Train B) = vA × 9
- Distance covered by Train B in 9 minutes (before meeting Train A) = vB × 9

Since both the trains cover the same distance when they meet, we can equate the above two equations to get:

vA × 9 = vB × 9
d/10 × 9 = d/tB × 9
tB = 10 minutes

Therefore, the total time taken by Train B to travel from station Y to station X is:

Time taken to meet Train A (at some point in between) + Time taken to travel from that point to station X
= 9 minutes + 10 minutes
= 19 minutes

Hence, the correct option is (c) 15.
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Community Answer
Trains A and B start traveling at the same time towards each other wit...
Here, we have the following:

Distance between stations X and Y = d units
Speed of train A = d/10 units/minutes
Speed of train B = d/Tb,
where Tb is total time taken by train B to cover distance d.
Let the trains meet after time T,
now, T + 9 = Tb (as mentioned in question, train B takes 9 minutes to reach other station after meeting the train).
So, we have the following:
Sum of distances covered by the 2 trains when they meet = distance between the two stations

=> T(d/10) + T(d/Tb) = d
=> T(d/10) + T(d/T+9) = d
=> T(T+9)/10(T+9) + 10T/10(T+9) = 1 (after taking d common on LHS and RHS)
=> T²+9T+10T = 10T+90
=> T²+9T-90 =0
=> (T-6)(T+15) = 0

Here, T = 6
Tb = 9 +T =9+6 = 15
Hence the answer is 15
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Trains A and B start traveling at the same time towards each other with constant speeds from stations X and Y, respectively. Train A reaches station Y in 10 minutes while train B takes 9 minutes to reach station X after meeting train A. Then the total time taken, in minutes, by train B to travel from station Y to station X isa)6b)10c)15d)12Correct answer is option 'C'. Can you explain this answer?
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