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SnCl₂ gives a precipitate with a solution of HgCl₂. In this process HgCl₂ is
  • a)
    Reduced
  • b)
    Oxidised
  • c)
    Converted into a complex compound containing both Sn and Hg
  • d)
    Converted into a chloro complex of Hg
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
SnCl gives a precipitate with a solution of HgCl. In this process HgCl...
Reduction of HgCl by SnCl

• When a solution of SnCl is added to a solution of HgCl, a white precipitate of Hg is formed.

• The reaction can be represented as follows:

SnCl₂ + HgCl₂ → SnCl₂ + Hg↓

• Here, SnCl acts as a reducing agent and reduces HgCl to Hg.

• Reduction is a process that involves the gain of electrons.

• In this reaction, SnCl is oxidized to SnCl₂, which means it loses electrons, while HgCl is reduced to Hg, which means it gains electrons.

• Therefore, option 'A' is the correct answer.

• This reaction is often used as a qualitative test for Hg ions.
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