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In a Wheatstone bridge all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, The equivalent resistance of the combination as seen by the battery is
  • a)
    R/4
  • b)
    R/2
  • c)
    R
  • d)
    2 R
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a Wheatstone bridge all the four arms have equal resistance R. If t...
Explanation:

Wheatstone Bridge:

- A Wheatstone bridge is a circuit used to measure an unknown electrical resistance by balancing two legs of a bridge circuit, one leg of which includes the unknown component.
- The Wheatstone bridge consists of four resistors connected in the form of a diamond as shown in the below figure.

![image.png](https://cdn1.byjus.com/wp-content/uploads/2018/11/Wheatstone-Bridge.png)

- The bridge is said to be balanced when the potential difference between points C and D is zero.
- At balance, the product of the resistances in the two legs of the bridge across the diagonal are equal. That is,

R1R3 = R2R4

- Here, R1, R2, R3, and R4 are the resistances of the four arms of the Wheatstone bridge.

Given:

- In the given Wheatstone bridge, all four arms have equal resistance R.
- The resistance of the galvanometer arm is also R.

To find:

- The equivalent resistance of the combination as seen by the battery.

Solution:

- Let's assume that the equivalent resistance of the combination is Req.
- At balance, the potential difference between points C and D is zero.
- This implies that the current passing through the galvanometer arm is zero.
- Therefore, the current passing through the resistors R and R is the same.
- Using Ohm's law, we can write the current passing through each resistor as:

I = V/R

- Here, V is the potential difference across the Wheatstone bridge.
- The potential difference across the resistors R and R is V/2.
- Therefore, the current passing through each resistor is given by:

I1 = I2 = (V/2)/R = V/2R

- The potential difference across the galvanometer arm is also V/2.
- Since the resistance of the galvanometer arm is R, the current passing through it is given by:

Ig = (V/2)/R = V/2R

- At balance, the current passing through the galvanometer arm is zero.
- Therefore, the potential difference across the galvanometer arm is also zero.
- This implies that the potential difference across the resistors R and R is also zero.
- Therefore, the potential difference across the two parallel resistors is zero.
- This implies that the equivalent resistance of the two parallel resistors is zero.
- Therefore, the equivalent resistance of the combination is given by:

Req = R + 0 + R = 2R

- Therefore, the correct option is (c) R.
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In a Wheatstone bridge all the four arms have equal resistance R. If the resistance of the galvanometer arm is also R, The equivalent resistance of the combination as seen by the battery isa)R/4b)R/2c)Rd)2 RCorrect answer is option 'C'. Can you explain this answer?
Question Description
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