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Three bags contain 18 balls of red and blue colours. The first bag contains 3 red and 3 blue balls. The second bag contains 4 red and 2 blue balls and the third bag contains 2 red and 4 blue balls. One ball is taken out at random from each bag. The probability of getting 2 red balls and 1 blue ball is
  • a)
    17/18
  • b)
    1/2
  • c)
    5/18
  • d)
    7/18
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Three bags contain 18 balls of red and blue colours. The first bag con...
To find the probability of getting 2 red balls and 1 blue ball, we need to consider the possible outcomes and the total number of outcomes.

Let's break down the problem into three parts:

1. Bag 1:
- Total number of balls = 3 red + 3 blue = 6
- Probability of selecting a red ball = 3/6 = 1/2
- Probability of selecting a blue ball = 3/6 = 1/2

2. Bag 2:
- Total number of balls = 4 red + 2 blue = 6
- Probability of selecting a red ball = 4/6 = 2/3
- Probability of selecting a blue ball = 2/6 = 1/3

3. Bag 3:
- Total number of balls = 2 red + 4 blue = 6
- Probability of selecting a red ball = 2/6 = 1/3
- Probability of selecting a blue ball = 4/6 = 2/3

Now, let's consider all the possible outcomes when we select one ball from each bag:

1. Red-Red-Red: The probability of this outcome is (1/2) * (2/3) * (1/3) = 2/18
2. Red-Red-Blue: The probability of this outcome is (1/2) * (2/3) * (2/3) = 4/18
3. Red-Blue-Red: The probability of this outcome is (1/2) * (1/3) * (1/3) = 1/18
4. Red-Blue-Blue: The probability of this outcome is (1/2) * (1/3) * (2/3) = 2/18
5. Blue-Red-Red: The probability of this outcome is (1/2) * (2/3) * (1/3) = 2/18
6. Blue-Red-Blue: The probability of this outcome is (1/2) * (2/3) * (2/3) = 4/18
7. Blue-Blue-Red: The probability of this outcome is (1/2) * (1/3) * (1/3) = 1/18
8. Blue-Blue-Blue: The probability of this outcome is (1/2) * (1/3) * (2/3) = 2/18

Now, let's calculate the total number of outcomes:
- Since we are selecting one ball from each bag, the total number of outcomes is the product of the number of balls in each bag, which is 6 * 6 * 6 = 216.

Finally, let's calculate the probability of getting 2 red balls and 1 blue ball:
- The probability of getting 2 red balls and 1 blue ball is the sum of the probabilities of the outcomes where we have 2 red balls and 1 blue ball: 2/18 + 4/18 + 1/18 + 2/18 = 9/18 = 1/2.

Therefore, the correct answer is option 'B' 1/2.
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Directions: Read the following information carefully and answer the question given below.A person has kept some sweets in 10 lockers for his 10 students, so that each of them chooses one. In each locker, there are some chocolates and some lollipops, where each lollipop costs Rs. 15 and each chocolate costs Rs. 25. Each locker is differently coloured i.e. yellow, blue, white, red, green, brown, pink, grey, orange and purple. Lockers are in two rows, one above another. The bottom row has lockers marked with numbers 1 to 5 (left to right) and the top row has lockers marked with numbers 6 to 10 (left to right). Locker number 1 is just below locker number 6 and in the same way, locker number 2 is just below locker number 7 and so on. Locker numbers 1 to 5 contain sweets worth Rs. 485 and locker numbers 6 to 10 contain sweets worth Rs. 570. There are neither less than 3 sweets nor more than 8 sweets in any locker. Locker number 9 is brown in colour. Locker number 5 has 4 lollipops and 4 chocolates. Locker of red colour is numbered 3 more than the locker of green colour and both are in the same row. Locker number 1 contains sweets worth Rs. 125. The red coloured locker has sweets worth Rs. 45 more than the green coloured locker. Only the purple coloured locker contains the maximum number of sweets. The pink coloured locker is just above the yellow coloured locker. Grey colour locker is numbered 3 more than the locker which is yellow in colour and both are in the same row. The locker number which is numbered 1 less than the orange coloured locker contains sweets worth Rs. 95. The blue coloured locker contains 2 lollipops. The white coloured locker contains 3 sweets. Sweets in the orange coloured locker are worth Rs. 5 less than the sweets in the pink coloured locker. The red and white coloured lockers contain the same number of lollipops. Sweets in the grey coloured locker are worth Rs. 10 less than the white coloured locker. Sweets in the pink and blue coloured lockers cost Rs. 190 altogether. The orange and brown coloured lockers contain equal number of chocolates. Locker number 2 has sweets worth Rs. 80.Q.How many chocolates are there in lockers 6 to 10 altogether?

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Three bags contain 18 balls of red and blue colours. The first bag contains 3 red and 3 blue balls. The second bag contains 4 red and 2 blue balls and the third bag contains 2 red and 4 blue balls. One ball is taken out at random from each bag. The probability of getting 2 red balls and 1 blue ball isa)17/18b)1/2c)5/18d)7/18Correct answer is option 'D'. Can you explain this answer?
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