Tickets numbered from 1 to 25 are mixed up together and a ticket is dr...
13 odd numbers are there.
p=Total no. of favourable outcomes / total of outcomes
=13/25
Tickets numbered from 1 to 25 are mixed up together and a ticket is dr...
Problem:
Tickets numbered from 1 to 25 are mixed up together and a ticket is drawn at random. What is the probability that the drawn ticket contains an odd number?
Solution:
To solve this problem, we need to determine the total number of outcomes and the number of favorable outcomes.
Total Number of Outcomes:
The total number of outcomes is the total number of tickets available, which is 25.
Number of Favorable Outcomes:
In this case, the favorable outcomes are the tickets that contain odd numbers. The odd numbers between 1 and 25 are:
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25
There are 13 odd numbers between 1 and 25.
Probability:
The probability of an event is defined as the number of favorable outcomes divided by the total number of outcomes.
Probability = Number of Favorable Outcomes / Total Number of Outcomes
In this case, the probability of drawing a ticket with an odd number is:
Probability = 13 / 25
Simplifying the fraction, we get:
Probability = 0.52
Converting this to a percentage, we get:
Probability = 52%
Therefore, the probability of drawing a ticket with an odd number is 52%.
Answer:
The correct answer is option (c) 13/25.
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.