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Ozonolysis of C₇H₁₄ gave 2-methyl-3-pentanone toluene. The alkene is
- a)2-Ethyl-3-methyl-1-butene
- b)3-Ethyl-2-methyl-3-butene
- c)2,5-Dimethyl-3, 4-dimethylhex-3-ene
- d)3-Ethyl-2-methyl-1-butene
Correct answer is option 'A'. Can you explain this answer?
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Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-E...
Explanation:
Ozonolysis is a process that cleaves an alkene or alkyne into smaller fragments using ozone. The products obtained from ozonolysis of an alkene or alkyne can be used to determine the structure of the starting compound.
In this question, ozonolysis of CH gives 2-methyl-3-pentanone toluene. We need to determine the structure of the starting alkene.
Steps involved in the ozonolysis of an alkene:
1. Ozonolysis of an alkene cleaves the double bond to form two carbonyl compounds.
2. One carbonyl compound contains a ketone group and the other contains an aldehyde group.
3. The aldehyde group is further oxidized to a carboxylic acid or a salt of a carboxylic acid, depending on the reaction conditions.
Using the products obtained from the ozonolysis of CH, we can determine the structure of the starting alkene as follows:
1. The ketone product obtained from ozonolysis is 2-methyl-3-pentanone. This indicates that the starting alkene must have a methyl group attached to the second carbon atom and a pentyl group attached to the third carbon atom.
2. The other product obtained from ozonolysis is toluene. Toluene can be formed from the oxidation of an alkyl group attached to a benzene ring. This indicates that the starting alkene must have an ethyl group attached to the first carbon atom, which can be oxidized to form the methyl group in toluene.
Therefore, the structure of the starting alkene is 2-Ethyl-3-methyl-1-butene, which is option A.
Ozonolysis is a process that cleaves an alkene or alkyne into smaller fragments using ozone. The products obtained from ozonolysis of an alkene or alkyne can be used to determine the structure of the starting compound.
In this question, ozonolysis of CH gives 2-methyl-3-pentanone toluene. We need to determine the structure of the starting alkene.
Steps involved in the ozonolysis of an alkene:
1. Ozonolysis of an alkene cleaves the double bond to form two carbonyl compounds.
2. One carbonyl compound contains a ketone group and the other contains an aldehyde group.
3. The aldehyde group is further oxidized to a carboxylic acid or a salt of a carboxylic acid, depending on the reaction conditions.
Using the products obtained from the ozonolysis of CH, we can determine the structure of the starting alkene as follows:
1. The ketone product obtained from ozonolysis is 2-methyl-3-pentanone. This indicates that the starting alkene must have a methyl group attached to the second carbon atom and a pentyl group attached to the third carbon atom.
2. The other product obtained from ozonolysis is toluene. Toluene can be formed from the oxidation of an alkyl group attached to a benzene ring. This indicates that the starting alkene must have an ethyl group attached to the first carbon atom, which can be oxidized to form the methyl group in toluene.
Therefore, the structure of the starting alkene is 2-Ethyl-3-methyl-1-butene, which is option A.
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Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer?
Question Description
Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer?.
Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ozonolysis of CH gave 2-methyl-3-pentanone toluene. The alkene isa)2-Ethyl-3-methyl-1-buteneb)3-Ethyl-2-methyl-3-butenec)2,5-Dimethyl-3, 4-dimethylhex-3-ened)3-Ethyl-2-methyl-1-buteneCorrect answer is option 'A'. Can you explain this answer?.
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