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In a class, 30% of the students passed in English, 20% of the students passed in Hindi and 10% passed in both. If a student is selected at random, what is the probability that he passed in English or Hindi?  
  • a)
    9/10
  • b)
    1/2
  • c)
    2/5
  • d)
    3/5
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a class, 30% of the students passed in English, 20% of the students...
Given:
- 30% of the students passed in English.
- 20% of the students passed in Hindi.
- 10% passed in both English and Hindi.

To find:
The probability that a randomly selected student passed in either English or Hindi.

Solution:
To solve this problem, we need to use the concept of probability and set theory. Let's break down the problem step by step.

Step 1: Find the probability of passing in English:
Given that 30% of the students passed in English, the probability of passing in English is 30% or 0.3.

Step 2: Find the probability of passing in Hindi:
Given that 20% of the students passed in Hindi, the probability of passing in Hindi is 20% or 0.2.

Step 3: Find the probability of passing in both English and Hindi:
Given that 10% of the students passed in both English and Hindi, the probability of passing in both is 10% or 0.1.

Step 4: Find the probability of passing in either English or Hindi:
To find the probability of passing in either English or Hindi, we need to subtract the probability of passing in both English and Hindi from the sum of the probabilities of passing in English and Hindi.

P(English or Hindi) = P(English) + P(Hindi) - P(English and Hindi)

P(English or Hindi) = 0.3 + 0.2 - 0.1

P(English or Hindi) = 0.4

Therefore, the probability that a randomly selected student passed in either English or Hindi is 0.4 or 40%.

Answer:
The correct answer is option C) 2/5.
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