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A hypothetical reaction X2 + Y→ 2XY follows the following mechanism:
X2 → X + X ... fast
X + Y2 →​​​​​​​ XY + Y … slow
X + Y →​​​​​​​ XY … fast
The order of the overall reaction is
  • a)
    2
  • b)
    3/2
  • c)
    1
  • d)
    0
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A hypothetical reactionX2+ Y2→2XY follows the following mechanism...
Given Mechanism:
- X2→X + X (fast)
- X + Y2→XY + Y (slow)
- X + Y→XY (fast)

Rate-determining step:
The slow step in the reaction mechanism is the rate-determining step, which is X + Y2→XY + Y.

Rate Law:
The rate law for this step is rate = k[X][Y2].

Overall Reaction Order:
The overall reaction order is the sum of the individual reaction orders in the rate-determining step.
- The reaction order with respect to X is 1 (from X in the rate law).
- The reaction order with respect to Y is 1 (from Y2 in the rate law).
Therefore, the overall reaction order is 1 + 1 = 2/2 = 3/2.
Therefore, the correct answer is option B.
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Community Answer
A hypothetical reactionX2+ Y2→2XY follows the following mechanism...
Rate = k[X][Y2]
But the rate law expression cannot be expressed in terms of a reaction intermediate.


Rate = 
Thus, order of the reaction 
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A hypothetical reactionX2+ Y2→2XY follows the following mechanism:X2→X + X ... fastX + Y2→XY + Y … slowX + Y→XY … fastThe order of the overall reaction isa)2b)3/2c)1d)0Correct answer is option 'B'. Can you explain this answer?
Question Description
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