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If f(x) =log x, prove that, f(1/x) =-f(x)?
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If f(x) =log x, prove that, f(1/x) =-f(x)?
Proof:

We need to prove that f(1/x) = -f(x), where f(x) = log x.

1. Finding f(1/x)

To find f(1/x), we substitute 1/x in place of x in the function f(x) = log x.

So, f(1/x) = log (1/x)

Using the property of logarithms, log (1/x) = log 1 - log x

Since log 1 = 0, we get f(1/x) = - log x

2. Proving f(1/x) = -f(x)

Now we need to prove that f(1/x) = -f(x), i.e., -log x = -log x.

This is true since the negative of a number is equal to the negative of that number.

Therefore, we have proved that f(1/x) = -f(x), where f(x) = log x.
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If f(x) =log x, prove that, f(1/x) =-f(x)?
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