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If f(x)=2^x, prove that f(x 3)-f(x-1) =15/2f(x)?
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If f(x)=2^x, prove that f(x 3)-f(x-1) =15/2f(x)?
Proof that f(x 3)-f(x-1) =15/2f(x) for f(x)=2^x


Step 1: Write out the equation


We are given the equation: f(x 3)-f(x-1) =15/2f(x)

Step 2: Substitute f(x) with 2^x


We substitute f(x) with 2^x to get:

2^(3x) - 2^(x-1) = 15/2 * 2^x

Step 3: Simplify the equation


We can simplify the equation using the laws of exponents:

2^(3x) = 2^(x+1) * 15/2

2^(3x) = 2^(x+1) * 15

Step 4: Simplify the exponents


We can simplify the exponents using the laws of exponents:

2^(2x) = 15

Step 5: Check the solution


We can check the solution by substituting 2^(2x) back into the original equation:

f(x 3)-f(x-1) = 2^(3x) - 2^(x-1)

= 2^(2x + x + 1) - 2^(x-1)

= 2^(2x) * 2^x * 2 - 2^(x) * 2^-1

= 2^(2x) * 2^x * (2 - 1/2)

= 2^(2x) * 2^x * 3/2

= 15/2 * 2^x

Therefore, the equation is true and we have proved that f(x 3)-f(x-1) =15/2f(x) for f(x)=2^x.
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If f(x)=2^x, prove that f(x 3)-f(x-1) =15/2f(x)?
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