An ant climbing up a vertical pole ascends 12 meters and slips down 5 ...
The ant would cover 7 × 8 = 56 meters in 16 hours.
Further, it would require 7/12 of the 17th hour to reach the top.
Thus time required = 16 hours 35 minutes
An ant climbing up a vertical pole ascends 12 meters and slips down 5 ...
Given information:
- The ant climbs up 12 meters and slips down 5 meters in every alternate hour.
- The height of the pole is 63 meters.
To find:
- How long will it take for the ant to reach the top of the pole?
Approach:
1. Calculate the net distance covered by the ant in each 2-hour period.
2. Divide the total height of the pole by the net distance covered to find the number of 2-hour periods required.
3. Convert the number of 2-hour periods into hours and minutes.
Solution:
Step 1: Calculate the net distance covered by the ant in each 2-hour period.
- In the first 2 hours, the ant climbs up 12 meters.
- In the next 2 hours, the ant climbs up 12 meters - slips down 5 meters = 7 meters.
- In the next 2 hours, the ant climbs up 12 meters.
- In the next 2 hours, the ant climbs up 12 meters - slips down 5 meters = 7 meters.
So, in every 4-hour period, the ant covers a net distance of 12 + 7 + 12 + 7 = 38 meters.
Step 2: Divide the total height of the pole by the net distance covered to find the number of 4-hour periods required.
- Total height of the pole = 63 meters.
- Number of 4-hour periods required = 63 meters / 38 meters = 1.6579.
Step 3: Convert the number of 4-hour periods into hours and minutes.
- The whole number part represents the number of complete 4-hour periods, which is 1.
- The decimal part represents the remaining time, which is 0.6579.
- Convert the decimal part into minutes: 0.6579 * 60 = 39.474 minutes.
Therefore, the ant will take 1 complete 4-hour period (or 16 hours) and approximately 39 minutes to reach the top of the pole.
Final answer:
The ant will take approximately 16 hours and 39 minutes to reach the top of the pole. Hence, option C is the correct answer.