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Integrating factor of differential equation cos x dy/dx+y sin x = 1 is
  • a)
    cos x
  • b)
    tan x
  • c)
    sec x
  • d)
    sin x
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Integrating factor of differential equation cos x dy/dx+y sin x = 1 is...
Solution:

The given differential equation is
cos x dy/dx + y sin x = 1

We need to find the integrating factor of this differential equation.

Integrating factor:
Let I be the integrating factor.
Multiplying both sides of the differential equation by I, we get
I cos x dy/dx + I y sin x = I

We know that the product rule of differentiation states that
(d/dx)(I y) = I dy/dx + y dI/dx

Comparing this with the above equation, we get
dI/dx = I sin x

Separating the variables, we get
dI/I = sin x dx

Integrating both sides, we get
ln |I| = -cos x + C

where C is the constant of integration.

Taking exponential on both sides, we get
|I| = e^(-cos x+C) = e^C e^(-cos x)

Since e^C is a positive constant, we can write
I = ± e^(-cos x)

However, we need to choose the positive sign since the integrating factor should be positive.
Therefore, the integrating factor of the given differential equation is
I = e^(-cos x) = sec x

Hence, Option C is the correct answer.
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Integrating factor of differential equation cos x dy/dx+y sin x = 1 isa)cos xb)tan xc)sec xd)sin xCorrect answer is option 'C'. Can you explain this answer?
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