A trapezoidal channel with side slopes of 1 to 1 has to be designed to...
Design of Trapezoidal Channel
Given Data
- Discharge (Q) = 9 m3/s
- Velocity (V) = 1.5 m/s
- Side Slopes = 1:1
Calculations
Step 1: Determine the Area of Cross-Section (A)
Since we know the discharge and velocity, we can calculate the area of cross-section using the formula:
A = Q / V
Substituting the given values, we get:
A = 9 / 1.5 = 6 m2
Step 2: Determine the Bottom Width (B)
Assuming a trapezoidal channel with side slopes of 1:1, we can use the formula for the area of a trapezoid to calculate the bottom width:
A = (B + b) * h / 2
where b = side slope height, h = depth of water
Since the side slopes are 1:1, b = h. Therefore, we can simplify the formula to:
A = B * h
Substituting the values of A and h, we get:
B = A / h = 6 / h
Step 3: Determine the Depth of Water (h)
We can use Manning's formula to calculate the depth of water:
V = (1 / n) * R2/3 * S1/2
where n = Manning's roughness coefficient, R = hydraulic radius, S = slope
Assuming a value of n = 0.015 for concrete lining, we can calculate the hydraulic radius using the formula:
R = A / P
where P = wetted perimeter
Since we know the bottom width and side slopes, we can calculate the wetted perimeter as:
P = B + 2 * h * sqrt(2) = 6 / h + 2 * h * sqrt(2)
Substituting the values of A, n, and P in Manning's formula, we get:
1.5 = (1 / 0.015) * (A / P)2/3 * S1/2
Solving for S, we get:
S = (1.5 * 0.015 / A2/3)2
Substituting the value of S in Manning's formula, we get:
h = (A / (0.015 * R * S1/2))3/5
Step 4: Determine the Area of