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In an examination, A attempted 80% of the questions with 50% accuracy and B attempted 60% of the questions with 80% accuracy. The negative marking is 25% for wrong answer, no negative marks for questions not attempted. Who got more marks?
- a)A
- b)B
- c)Both got the same marks.
- d)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In an examination, A attempted 80% of the questions with 50% accuracy ...
Let the total number of questions be 100 and each be of 4 marks.
Therefore, 1 mark is deducted for wrong answer.
For A, number of questions attempted = 80
Number of right questions = 40
Number of wrong questions = 40
Total marks obtained by A = 4 × (Number of right questions) - 1 × (Number of wrong questions)
= 4 × 40 - 1 × 40 = 160 - 40 = 120
For B, number of questions attempted = 60
Number of right questions = 48
Number of wrong questions = 12
Total marks obtained by B = 4 × (Number of right questions) - 1 × (Number of wrong questions)
= 4 × 48 - 1 × 12 = 192 - 12 = 180
B got more marks.
Therefore, 1 mark is deducted for wrong answer.
For A, number of questions attempted = 80
Number of right questions = 40
Number of wrong questions = 40
Total marks obtained by A = 4 × (Number of right questions) - 1 × (Number of wrong questions)
= 4 × 40 - 1 × 40 = 160 - 40 = 120
For B, number of questions attempted = 60
Number of right questions = 48
Number of wrong questions = 12
Total marks obtained by B = 4 × (Number of right questions) - 1 × (Number of wrong questions)
= 4 × 48 - 1 × 12 = 192 - 12 = 180
B got more marks.
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Community Answer
In an examination, A attempted 80% of the questions with 50% accuracy ...
Given Information:
- A attempted 80% of the questions with 50% accuracy.
- B attempted 60% of the questions with 80% accuracy.
- Negative marking is 25% for wrong answers.
To find:
- Who got more marks, A or B?
Approach:
1. Calculate the number of questions attempted correctly by A and B.
2. Calculate the number of questions attempted wrongly by A and B.
3. Calculate the total marks obtained by A and B.
4. Compare the total marks obtained by A and B to determine who got more marks.
Calculations:
1. Number of questions attempted correctly by A:
- A attempted 80% of the questions, so the number of questions attempted by A = 80% of total questions.
- A has 50% accuracy, so the number of questions attempted correctly by A = 50% of questions attempted by A.
- Therefore, the number of questions attempted correctly by A = (80/100) * (50/100) * total questions.
2. Number of questions attempted wrongly by A:
- A attempted 80% of the questions, so the number of questions attempted by A = 80% of total questions.
- A has 50% accuracy, so the number of questions attempted wrongly by A = 50% of questions attempted by A.
- Therefore, the number of questions attempted wrongly by A = (80/100) * (50/100) * total questions.
3. Number of questions attempted correctly by B:
- B attempted 60% of the questions, so the number of questions attempted by B = 60% of total questions.
- B has 80% accuracy, so the number of questions attempted correctly by B = 80% of questions attempted by B.
- Therefore, the number of questions attempted correctly by B = (60/100) * (80/100) * total questions.
4. Number of questions attempted wrongly by B:
- B attempted 60% of the questions, so the number of questions attempted by B = 60% of total questions.
- B has 80% accuracy, so the number of questions attempted wrongly by B = 20% of questions attempted by B.
- Therefore, the number of questions attempted wrongly by B = (60/100) * (20/100) * total questions.
5. Total marks obtained by A:
- Each correct answer carries 1 mark.
- Each wrong answer carries -0.25 mark (due to negative marking).
- Therefore, total marks obtained by A = (number of questions attempted correctly by A * 1) + (number of questions attempted wrongly by A * (-0.25)).
6. Total marks obtained by B:
- Each correct answer carries 1 mark.
- Each wrong answer carries -0.25 mark (due to negative marking).
- Therefore, total marks obtained by B = (number of questions attempted correctly by B * 1) + (number of questions attempted wrongly by B * (-0.25)).
Comparison:
- Compare the total marks obtained by A and B to determine who got more marks.
- If total marks obtained by A > total marks obtained by B, then A got
- A attempted 80% of the questions with 50% accuracy.
- B attempted 60% of the questions with 80% accuracy.
- Negative marking is 25% for wrong answers.
To find:
- Who got more marks, A or B?
Approach:
1. Calculate the number of questions attempted correctly by A and B.
2. Calculate the number of questions attempted wrongly by A and B.
3. Calculate the total marks obtained by A and B.
4. Compare the total marks obtained by A and B to determine who got more marks.
Calculations:
1. Number of questions attempted correctly by A:
- A attempted 80% of the questions, so the number of questions attempted by A = 80% of total questions.
- A has 50% accuracy, so the number of questions attempted correctly by A = 50% of questions attempted by A.
- Therefore, the number of questions attempted correctly by A = (80/100) * (50/100) * total questions.
2. Number of questions attempted wrongly by A:
- A attempted 80% of the questions, so the number of questions attempted by A = 80% of total questions.
- A has 50% accuracy, so the number of questions attempted wrongly by A = 50% of questions attempted by A.
- Therefore, the number of questions attempted wrongly by A = (80/100) * (50/100) * total questions.
3. Number of questions attempted correctly by B:
- B attempted 60% of the questions, so the number of questions attempted by B = 60% of total questions.
- B has 80% accuracy, so the number of questions attempted correctly by B = 80% of questions attempted by B.
- Therefore, the number of questions attempted correctly by B = (60/100) * (80/100) * total questions.
4. Number of questions attempted wrongly by B:
- B attempted 60% of the questions, so the number of questions attempted by B = 60% of total questions.
- B has 80% accuracy, so the number of questions attempted wrongly by B = 20% of questions attempted by B.
- Therefore, the number of questions attempted wrongly by B = (60/100) * (20/100) * total questions.
5. Total marks obtained by A:
- Each correct answer carries 1 mark.
- Each wrong answer carries -0.25 mark (due to negative marking).
- Therefore, total marks obtained by A = (number of questions attempted correctly by A * 1) + (number of questions attempted wrongly by A * (-0.25)).
6. Total marks obtained by B:
- Each correct answer carries 1 mark.
- Each wrong answer carries -0.25 mark (due to negative marking).
- Therefore, total marks obtained by B = (number of questions attempted correctly by B * 1) + (number of questions attempted wrongly by B * (-0.25)).
Comparison:
- Compare the total marks obtained by A and B to determine who got more marks.
- If total marks obtained by A > total marks obtained by B, then A got
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In an examination, A attempted 80% of the questions with 50% accuracy and B attempted 60% of the questions with 80% accuracy. The negative marking is 25% for wrong answer, no negative marks for questions not attempted. Who got more marks?a)Ab)Bc)Both got the same marks.d)Cannot be determinedCorrect answer is option 'B'. Can you explain this answer?
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