What will be the time period of a simple pendulum of length 9.8/Π^2 metre? g=9.8m/s^2.?

Question

Answer

Calculating the Time Period of a Simple Pendulum

A simple pendulum is a weight suspended from a string or wire that swings back and forth under the influence of gravity. The time period of a simple pendulum is the time it takes to complete one full swing.

Formula for Time Period of a Simple Pendulum

The time period of a simple pendulum can be calculated using the following formula:

Time period (T) = 2π √(L/g)

T = time period in seconds

π = pi (approximately 3.14)

L = length of the pendulum in metres

g = acceleration due to gravity (9.8 m/s^2)

Substituting Values in the Formula

Given the length of the pendulum is 9.8/π^2 metre, we can substitute this value into the formula:

T = 2π √(9.8/π^2)/9.8

Simplifying this equation:

T = 2π/√π^2

T = 2π/π

T = 2 seconds

Explanation

The time period of a simple pendulum is directly proportional to the square root of its length and inversely proportional to the acceleration due to gravity. Therefore, as the length of the pendulum increases, the time period increases, and as the acceleration due to gravity increases, the time period decreases.

In this case, the length of the pendulum is relatively small, but the acceleration due to gravity is standard at 9.8 m/s^2. Therefore, the time period is relatively short at 2 seconds.

Answer

2 sec

Answer

Let, T= time period, L= length of pendulum, g= acceleration due to gravity.
now,
we know that,
l= 9.8 m,
g= 9.8m/s^2

then by formula,
T= 2π√(l/g)
T = 2×22/7×√(9.8/9.8)
T= 44/7×1
T= 44/7 second
T= 6.28 seconds.

thanks for asking.

Answer

2 sec

Answer

Plese explain

Answer

2 second

Answer

Time period of a pendulum is 2π√(l/g) = 2π  √9.8/9.8*π^2 = 2π*1/π = 2hence the time period is 2

Answer

2 sec

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