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A loaf of bread with weight 60 grams is cut into three unequal pieces. The ratio of the weights of heaviest and the lightest pieces is 5 : 1. If the middle weighted piece is 18 grams heavier than the lightest, then what is the weight of the heaviest piece?
  • a)
    24 grams
  • b)
    30 grams
  • c)
    36 grams
  • d)
    40 grams
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A loaf of bread with weight 60 grams is cut into three unequal pieces....
Assume the weight of the heaviest piece = 5x
Then, the weight of the lightest piece = x
So, the weight of medium weighted piece = x + 18
∴ (5x) + (x + 18) + (x) = 60
⇒ x = 6
So, the weight of the heaviest piece = 5 × 6 = 30 grams
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Community Answer
A loaf of bread with weight 60 grams is cut into three unequal pieces....
Given:
- Weight of the loaf of bread = 60 grams
- The loaf of bread is cut into three unequal pieces
- Ratio of the weights of the heaviest and the lightest pieces = 5:1
- The middle weighted piece is 18 grams heavier than the lightest piece

To find:
- The weight of the heaviest piece

Solution:
Step 1: Assign variables
Let the weight of the lightest piece be x grams.
Then, the weight of the middle piece is (x + 18) grams.
And the weight of the heaviest piece is 5x grams.

Step 2: Form equations
According to the given information, we can form the following equations:
- x + (x + 18) + 5x = 60 (as the sum of the weights of the three pieces is equal to the weight of the loaf of bread)
- (7x + 18) = 60

Step 3: Solve the equation
(7x + 18) = 60
7x = 60 - 18
7x = 42
x = 42/7
x = 6

Step 4: Find the weight of the heaviest piece
The weight of the heaviest piece = 5x = 5 * 6 = 30 grams

Therefore, the weight of the heaviest piece is 30 grams.
Hence, option B is the correct answer.
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