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A bullet comes out of the barrel of gun of length 2m witha speed 80 ms-1. The average acceleration of the bullet is
  • a)
    1.6 ms-2
  • b)
    160 ms-2
  • c)
    1600 ms-2
  • d)
    16 ms-2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A bullet comes out of the barrel of gun of length 2m witha speed 80 ms...
Given:
Length of the gun, l = 2m
Speed of the bullet, v = 80 ms-1

To find:
Average acceleration of the bullet

Formula used:
Average acceleration, a = v^2/2l

Calculation:
Substituting the given values in the formula, we get
a = (80)^2/(2 x 2)
a = 1600/4
a = 400 ms-2

Therefore, the average acceleration of the bullet is 400 ms-2, which is equal to option C.

Explanation:
The average acceleration of the bullet is the change in velocity per unit time. In this case, the bullet goes from rest to a speed of 80 ms-1 in a distance of 2m. The formula used to calculate the average acceleration of the bullet is v^2/2l, where v is the final velocity and l is the length of the gun.

Substituting the given values in the formula, we get the average acceleration of the bullet as 400 ms-2. This means that for every second, the speed of the bullet increases by 400 ms-1. Hence, option C is the correct answer.
Free Test
Community Answer
A bullet comes out of the barrel of gun of length 2m witha speed 80 ms...
Average acclaration. = v²/2l

a =80²/2×2
=6400/4
=1600
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A bullet comes out of the barrel of gun of length 2m witha speed 80 ms-1. The average acceleration of the bullet isa)1.6 ms-2b)160 ms-2c)1600 ms-2d)16 ms-2Correct answer is option 'C'. Can you explain this answer?
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