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A 5 gm bullet acquires a speed of 120 m/s in a gun with barrrel length 2m the average force exerted on the bullet is?
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A 5 gm bullet acquires a speed of 120 m/s in a gun with barrrel length...
Calculation of Average Force Exerted on the Bullet


Given Data:


  • Mass of bullet (m) = 5 gm = 0.005 kg

  • Velocity of bullet (v) = 120 m/s

  • Length of barrel (s) = 2 m



Formula:

The average force exerted on the bullet is given by the formula:

F = m(v^2)/(2s)


Calculation:

Substituting the given values in the formula:

F = 0.005 x (120^2)/(2 x 2) = 180 N


Explanation:

When the trigger of a gun is pressed, a force is exerted on the bullet by the expanding gases in the gunpowder. This force propels the bullet forward through the barrel of the gun. The length of the barrel determines the amount of time the force acts on the bullet, which in turn determines the final velocity of the bullet.

The average force exerted on the bullet can be calculated using the formula F = m(v^2)/(2s), where m is the mass of the bullet, v is the velocity of the bullet, and s is the length of the barrel.

In this case, the mass of the bullet is 0.005 kg, the velocity of the bullet is 120 m/s, and the length of the barrel is 2 m. Substituting these values in the formula, we get an average force of 180 N.
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A 5 gm bullet acquires a speed of 120 m/s in a gun with barrrel length...
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