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Consider the following four electrodes
A = Cu+2 0.0001 M | C u s
B = Cu+2 0.1 M | C u s
C = Cu+2 0.01 M | C u s
D = Cu+2 0.001 M | C u s
If the standard reduction potential of Cu+2 ∕ C u is + 0.34 V , the reduction potential (in volts) of the above electrodes follow the order
  • a)
    A > D > C > B
  • b)
    B > C > D > A
  • c)
    C > D > B > A
  • d)
    A > B > C > D
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider the following four electrodesA = Cu+2 0.0001 M | C u sB = Cu+...
The reduction potential of Cu2+/Cu half-cell depends on the concentration of Cu2+ ions in the solution. The lower the concentration, the more negative the reduction potential will be. Therefore, the order of reduction potential for the given electrodes will be:

D (0.34 - 0.059 log(0.001/1)) = 0.277 V
A (0.34 - 0.059 log(0.0001/1)) = 0.244 V
C (0.34 - 0.059 log(0.01/1)) = 0.207 V
B (0.34 - 0.059 log(0.1/1)) = 0.170 V

Therefore, the correct order is: B < c="" />< a="" />< d.="" answer:="" (c)="" d.="" answer:="" />
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Consider the following four electrodesA = Cu+2 0.0001 M | C u sB = Cu+2 0.1 M | C u sC = Cu+2 0.01 M | C u sD = Cu+2 0.001 M | C u sIf the standard reduction potential of Cu+2 C u is + 0.34 V , the reduction potential (in volts) of the above electrodes follow the ordera)A > D > C > Bb)B > C > D > Ac)C > D > B > Ad)A > B > C > DCorrect answer is option 'B'. Can you explain this answer?
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Consider the following four electrodesA = Cu+2 0.0001 M | C u sB = Cu+2 0.1 M | C u sC = Cu+2 0.01 M | C u sD = Cu+2 0.001 M | C u sIf the standard reduction potential of Cu+2 C u is + 0.34 V , the reduction potential (in volts) of the above electrodes follow the ordera)A > D > C > Bb)B > C > D > Ac)C > D > B > Ad)A > B > C > DCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider the following four electrodesA = Cu+2 0.0001 M | C u sB = Cu+2 0.1 M | C u sC = Cu+2 0.01 M | C u sD = Cu+2 0.001 M | C u sIf the standard reduction potential of Cu+2 C u is + 0.34 V , the reduction potential (in volts) of the above electrodes follow the ordera)A > D > C > Bb)B > C > D > Ac)C > D > B > Ad)A > B > C > DCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following four electrodesA = Cu+2 0.0001 M | C u sB = Cu+2 0.1 M | C u sC = Cu+2 0.01 M | C u sD = Cu+2 0.001 M | C u sIf the standard reduction potential of Cu+2 C u is + 0.34 V , the reduction potential (in volts) of the above electrodes follow the ordera)A > D > C > Bb)B > C > D > Ac)C > D > B > Ad)A > B > C > DCorrect answer is option 'B'. Can you explain this answer?.
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