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A sample of carbon that contains 95% by mole carbon-12 and 5% by mole carbon-14 isotopes .The average atomic mass is a)12.5 b)12.1 c)6.05 d)6.1?
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A sample of carbon that contains 95% by mole carbon-12 and 5% by mole ...
Answer:

Given: A sample of carbon that contains 95% by mole carbon-12 and 5% by mole carbon-14 isotopes.

To find: The average atomic mass of the sample.

Solution:

Step 1: Find the atomic mass of carbon-12 and carbon-14.

- The atomic mass of carbon-12 is 12 u.
- The atomic mass of carbon-14 is 14 u.

Step 2: Calculate the weighted average atomic mass of the sample.

- The weighted average atomic mass is the sum of the products of the atomic masses and their mole fractions.

- Let x be the mole fraction of carbon-12 and y be the mole fraction of carbon-14.

- x + y = 1 (since the sample contains only these two isotopes)

- x = 0.95 and y = 0.05 (given)

- The weighted average atomic mass = (x * 12 u) + (y * 14 u)

= (0.95 * 12 u) + (0.05 * 14 u)

= 11.4 u + 0.7 u

= 12.1 u

Answer: The average atomic mass of the sample is 12.1 u.

Therefore, the correct option is (d) 6.1.
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A sample of carbon that contains 95% by mole carbon-12 and 5% by mole carbon-14 isotopes .The average atomic mass is a)12.5 b)12.1 c)6.05 d)6.1?
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