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For a polyphase system, the number of Wattmeter required to measure power is equal to _______
  • a)
    Number of wires
  • b)
    One less than number of wires
  • c)
    Number of phases
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
For a polyphase system, the number of Wattmeter required to measure po...
The number of Wattmeter required to measure power in a polyphase system is determined using Blondell’s theorem. According to this, the number of Wattmeter required is equal to one less than the number of wires in the circuit. For example, in a three phase, four wire system (Star network), the number of Wattmeter required is three.
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For a polyphase system, the number of Wattmeter required to measure po...
Understanding Polyphase Systems
In a polyphase system, such as a three-phase system, power measurement can be efficiently conducted using wattmeters. The rule for determining the number of wattmeters required is directly related to the number of wires in the system.
Key Concept: Wattmeter Requirement
- For a balanced polyphase system, the number of wattmeters needed is equal to the number of phases minus one.
- This principle holds true for systems with three or more phases.
Why One Less than Number of Wires?
- In a typical three-phase system, there are three conductors (wires).
- To measure power accurately, one wattmeter can be used to measure the power in any two phases, while the third phase can be deduced from the first two.
Example: Three-Phase System
- In a three-phase system:
- Total wires = 3
- Required wattmeters = 3 - 1 = 2
- Therefore, using two wattmeters, you can measure the total power efficiently.
Conclusion
The correct answer, "one less than the number of wires," reflects the efficiency of power measurement in polyphase systems. This method allows for accurate calculations without the need for excessive equipment. Thus, when analyzing polyphase systems, always remember that the number of wattmeters required is equal to the number of wires minus one.
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