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Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19?
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Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,...
Creating B-Tree


  1. Initially, the tree is empty.

  2. The first key value 2 is added to the tree as the root node.

  3. The second key value 3 is added to the root node.

  4. The third key value 5 is added to the root node.

  5. The root node is split into two nodes, with 3 being the new root node and 2 and 5 being its children.

  6. The fourth key value 7 is added to the left child of the root node.

  7. The fifth key value 11 is added to the right child of the root node.

  8. The sixth key value 17 is added to the right child of the root node.

  9. The right child of the root node is split into two nodes, with 11 being the new right child and 17 being its child.

  10. The seventh key value 19 is added to the right child of the root node.

  11. The right child of the root node is split into two nodes, with 11 being the new right child and 17 and 19 being its children.

  12. The eighth key value 23 is added to the right child of the root node.

  13. The right child of the root node is split into two nodes, with 11 and 19 being the children of the left split node and 23 being the child of the right split node.

  14. The ninth key value 29 is added to the right child of the root node.

  15. The right child of the root node is split into two nodes, with 11 and 19 being the children of the left split node and 23 and 29 being the children of the right split node.

  16. The tenth key value 31 is added to the right child of the root node.

  17. The right child of the root node is split into two nodes, with 11 and 19 being the children of the left split node and 23, 29, and 31 being the children of the right split node.


Performing Operations


  1. Insert 9


    • Starting from the root node, we traverse the tree to find the node where 9 should be inserted.

    • We find that 9 should be inserted in the left child of the node containing 11.

    • The left child of the node containing 11 has only three children, so we simply insert 9 into that node.


  2. Insert 10


    • Starting from the root node, we traverse the tree to find the node where 10 should be inserted.

    • We find that 10 should be inserted in the left child of the node containing 11.

    • The left child of the node containing 11 has only three children, so we simply insert 10 into that node.


  3. Insert 8


    • Starting from the root node, we traverse the tree to find the node where 8 should be inserted.

    • We find that 8 should be inserted in the left child of the node containing 7.

    • The left child of the
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Introduction:To find the inverse of a matrix A using elementary transformations, we need to perform a series of row operations until A is transformed into the identity matrix I. Simultaneously, we perform the same row operations on the identity matrix I and obtain the inverse matrix A^-1.Given Matrix:A = [1 2 2 -1]Augmented Matrix:We will augment the given matrix A with the identity matrix I as follows:[A | I] = [1 2 2 -1 | 1 0 0 1]Row Operations:Perform the following row operations to transform A into I:1. R2 = R2 - 2R1[A | I] = [1 2 2 -1 | 1 0 0 1] [0 -2 -2 1 | -2 0 0 0] 2. R2 = -1/2R2[A | I] = [1 2 2 -1 | 1 0 0 1] [0 1 1/2 -1/2 | 1 0 0 0] 3. R1 = R1 - 2R2[A | I] = [1 0 1 -2 | -1 0 0 1] [0 1 1/2 -1/2 | 1 0 0 0] 4. R1 = R1 + R2[A | I] = [1 0 3/2 -5/2 | 0 0 0 1] [0 1 1/2 -1/2 | 1 0 0 0] Final Result:After performing the row operations, the matrix A is transformed into the identity matrix I. The inverse matrix A^-1 is given by the augmented matrix on the right side:A^-1 = [0 0 0 1 | 0 0 0 1] [0 1 1/2 -1/2 | 1 0 0 0]Explanation:By using elementary transformations, we performed a series of row operations on the given matrix A to transform it into the identity matrix I. Simultaneously, we performed the same row operations on the identity matrix I to obtain the inverse matrix A^-1. These row operations include adding or subtracting multiples of one row from another and multiplying a row by a constant. These operations ensure that the resulting matrix A^-1, when multiplied with the original matrix A, yields the identity matrix I. Therefore, A^-1 is the inverse of matrix A.

Read the passage carefully and choose the best answer for the question out of the four alternatives.A British survey found that 44 percent of firms, which started using robots; met with initial failure and 22 percent abandoned them altogether, mainly because of inadequate technological know-how and skills at all plant levels.Robotization is by and large a viable proposition. These machines can work round the clock, raise output, protect the quality and enhance industrial competitiveness.One robot can replace between two and five production workers while providing cheaper labour. In the US car industry, a man-hour costs around 23 but a robot-hour costs only 6.Certain jobs, mostly simple or hazardous ones, are irretrievably lost to robotics. Thus spot welders, press operators, spray painters, cleaners, machine leaders, and operators of grinding and polishing machines are endangered species.Q. What did the writer say that in view of initial failure?

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Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19?
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Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19?.
Solutions for Prepare B+ Tree for the following set of key values (2,3,5,7,11,17,19,23,29,31)Assume that the tree is initially empty and values are added in ascending order. Construct B+ tree for the cases where the number of pointers that fit one node is four. After creation of B+ tree perform following series of operations: a)Insert 9 b)Insert 10 c)Insert 8 d)Delete 23 e)Delete 19? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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