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The chainages (m) and corresponding perpendicular offsets(m) taken from a chain line to an irregular boundary were (0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00) and (210, 5.80). The area (m2) between the chain line and the irregular boundary by Simpson's rule is
  • a)
    681
  • b)
    767.825
  • c)
    781
  • d)
    790.5
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The chainages (m) and corresponding perpendicular offsets(m) taken fro...
Given data:
Chainages (m) and corresponding perpendicular offsets (m) taken from a chain line to an irregular boundary are as follows:

(0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00), and (210, 5.80)

To find:
The area (m²) between the chain line and the irregular boundary using Simpson's rule.

Explanation:
Simpson's rule is a numerical integration method used to approximate the area under a curve. It provides a better approximation compared to other methods like the trapezoidal rule when the curve is not linear.

The formula for Simpson's rule is:
Area = (h/3) * [y0 + 4y1 + 2y2 + 4y3 + 2y4 + ... + 2yn-2 + 4yn-1 + yn]

Where:
h = step size (difference between consecutive chainages)
y0, y1, y2, ..., yn = perpendicular offsets at respective chainages

Step 1: Calculate the step size (h)
h = (210 - 0) / (n-1)
= 210 / (8-1)
= 210 / 7
= 30

Step 2: Calculate the sum of perpendicular offsets based on the given data:
Sum of even offsets = y2 + y4 + y6
= 3.80 + 4.65 + 5.00
= 13.45

Sum of odd offsets = y1 + y3 + y5 + y7
= 2.65 + 3.75 + 3.60 + 5.80
= 15.80

Step 3: Calculate the area using Simpson's rule:
Area = (h/3) * [y0 + 4y1 + 2y2 + 4y3 + 2y4 + 4y5 + 2y6 + 4y7 + yn]
= (30/3) * [0 + 4(2.65) + 2(3.80) + 4(3.75) + 2(4.65) + 4(3.60) + 2(5.00) + 4(5.80) + 0]
= 10 * [0 + 10.60 + 7.60 + 15.00 + 9.30 + 14.40 + 10.00 + 23.20 + 0]
= 10 * 90.10
= 901

Step 4: Calculate the adjusted area by multiplying by the step size (h/2):
Adjusted area = Area * (h/2)
= 901 * (30/2)
= 901 * 15
= 13515

Step 5: Round the final result to the nearest whole number:
Final area = 13515 (rounded to the nearest whole number)
=
Free Test
Community Answer
The chainages (m) and corresponding perpendicular offsets(m) taken fro...
Simpson's Rule:
In this rule, the boundaries between the ends of ordinates are assumed to form an arc of a parabola. Hence, Simpson's rule is sometimes called the parabolic rule.
The rule may be stated as follows,
To the sum of the first and the last ordinate, four times the sum of even ordinates and twice the sum of the remaining odd ordinates are added. This total sum is multiplied by the common distance. One-third of this product is the required area.
The area is given by Simpson's rule:

where O1, O2, O3, .........On is the offset
Limitation: 
This rule is applicable only when the number of divisions is even, i.e., the number of ordinates is odd.
Calculation

Simpson's Rule :- If this rule is to be applied, the number of ordinates must be odd. But here the number of ordinate is even (eight)
so, Simpson's rule is applied from 01 to 07 and the area between 07 and 08 is found out by trapezoidal rule. 

A1 = 10 × (5 + 40 + 16.9)
A1 = 619 m2 
A= 30/2(5.00+5.80)
A2 = 162 m2
∴ Total area = A1 + A2
= 619 + 162 = 781 m2
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The chainages (m) and corresponding perpendicular offsets(m) taken from a chain line to an irregular boundary were (0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00) and (210, 5.80). The area (m2) between the chain line and the irregular boundary by Simpsons rule isa)681b)767.825c)781d)790.5Correct answer is option 'C'. Can you explain this answer?
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The chainages (m) and corresponding perpendicular offsets(m) taken from a chain line to an irregular boundary were (0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00) and (210, 5.80). The area (m2) between the chain line and the irregular boundary by Simpsons rule isa)681b)767.825c)781d)790.5Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The chainages (m) and corresponding perpendicular offsets(m) taken from a chain line to an irregular boundary were (0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00) and (210, 5.80). The area (m2) between the chain line and the irregular boundary by Simpsons rule isa)681b)767.825c)781d)790.5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The chainages (m) and corresponding perpendicular offsets(m) taken from a chain line to an irregular boundary were (0, 0), (30, 2.65), (60, 3.80), (90, 3.75), (120, 4.65), (150, 3.60), (180, 5.00) and (210, 5.80). The area (m2) between the chain line and the irregular boundary by Simpsons rule isa)681b)767.825c)781d)790.5Correct answer is option 'C'. Can you explain this answer?.
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