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A man started a piece of work on the first day. The second day, one more person joined him. The next day, one more person joined. Everyday, one new person joined until the work got completed. If the work was completed in 15 days, how many days would 10 men take to complete the same work, given that they worked regularly and efficiency of all men is the same?
- a)6 days
- b)8 days
- c)10 days
- d)12 days
- e)15 days
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A man started a piece of work on the first day. The second day, one mo...
Let one day work of a man = x units
∵1st day = x
2nd day = 2x
……………..
……………
15th day = 15x
Total work done in 15 days = x + 2x + 3x + ... + 15x = 120x
So, time taken to complete 120x work by 10 men is 120x/10x = 12 days
∵1st day = x
2nd day = 2x
……………..
……………
15th day = 15x
Total work done in 15 days = x + 2x + 3x + ... + 15x = 120x
So, time taken to complete 120x work by 10 men is 120x/10x = 12 days
Most Upvoted Answer
A man started a piece of work on the first day. The second day, one mo...
Given:
- A man started a piece of work on the first day.
- The second day, one more person joined him.
- The next day, one more person joined.
- Everyday, one new person joined until the work got completed.
- The work was completed in 15 days.
To find:
How many days would 10 men take to complete the same work, given that they worked regularly and efficiency of all men is the same?
Assumption:
Let's assume that the work is such that it can be divided equally among the men.
Explanation:
Let's analyze the situation step by step:
Day 1:
- 1 man starts the work.
Day 2:
- 1 more person joins, so there are 2 men working.
- The work is divided equally between them, so they each do half of the work.
Day 3:
- 1 more person joins, so there are 3 men working.
- The work is divided equally between them, so they each do one-third of the work.
Day 4:
- 1 more person joins, so there are 4 men working.
- The work is divided equally between them, so they each do one-fourth of the work.
Day 5:
- 1 more person joins, so there are 5 men working.
- The work is divided equally between them, so they each do one-fifth of the work.
Day 6:
- 1 more person joins, so there are 6 men working.
- The work is divided equally between them, so they each do one-sixth of the work.
Day 7:
- 1 more person joins, so there are 7 men working.
- The work is divided equally between them, so they each do one-seventh of the work.
Day 8:
- 1 more person joins, so there are 8 men working.
- The work is divided equally between them, so they each do one-eighth of the work.
Day 9:
- 1 more person joins, so there are 9 men working.
- The work is divided equally between them, so they each do one-ninth of the work.
Day 10:
- 1 more person joins, so there are 10 men working.
- The work is divided equally between them, so they each do one-tenth of the work.
Day 11-15:
- The work is divided equally among the 10 men, so they each do one-tenth of the work each day.
Conclusion:
- From the above analysis, we can see that 10 men would take 10 days to complete the same work.
- A man started a piece of work on the first day.
- The second day, one more person joined him.
- The next day, one more person joined.
- Everyday, one new person joined until the work got completed.
- The work was completed in 15 days.
To find:
How many days would 10 men take to complete the same work, given that they worked regularly and efficiency of all men is the same?
Assumption:
Let's assume that the work is such that it can be divided equally among the men.
Explanation:
Let's analyze the situation step by step:
Day 1:
- 1 man starts the work.
Day 2:
- 1 more person joins, so there are 2 men working.
- The work is divided equally between them, so they each do half of the work.
Day 3:
- 1 more person joins, so there are 3 men working.
- The work is divided equally between them, so they each do one-third of the work.
Day 4:
- 1 more person joins, so there are 4 men working.
- The work is divided equally between them, so they each do one-fourth of the work.
Day 5:
- 1 more person joins, so there are 5 men working.
- The work is divided equally between them, so they each do one-fifth of the work.
Day 6:
- 1 more person joins, so there are 6 men working.
- The work is divided equally between them, so they each do one-sixth of the work.
Day 7:
- 1 more person joins, so there are 7 men working.
- The work is divided equally between them, so they each do one-seventh of the work.
Day 8:
- 1 more person joins, so there are 8 men working.
- The work is divided equally between them, so they each do one-eighth of the work.
Day 9:
- 1 more person joins, so there are 9 men working.
- The work is divided equally between them, so they each do one-ninth of the work.
Day 10:
- 1 more person joins, so there are 10 men working.
- The work is divided equally between them, so they each do one-tenth of the work.
Day 11-15:
- The work is divided equally among the 10 men, so they each do one-tenth of the work each day.
Conclusion:
- From the above analysis, we can see that 10 men would take 10 days to complete the same work.
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A man started a piece of work on the first day. The second day, one more person joined him. The next day, one more person joined. Everyday, one new person joined until the work got completed. If the work was completed in 15 days, how many days would 10 men take to complete the same work, given that they worked regularly and efficiency of all men is the same?a)6 daysb)8 daysc)10 daysd)12 dayse)15 daysCorrect answer is option 'D'. Can you explain this answer?
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