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A number consists of 3 consecutive digits, such that the digit in the units place being the greatest of the three. The number formed by reversing the digits exceeds the original number by 22 times the sum of the digit. Find the number.
  • a)
    231
  • b)
    234
  • c)
    233
  • d)
    232
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A number consists of 3 consecutive digits, such that the digit in the ...
Let the hundreds digit be a.
Then, the tens digit = a + 1 and the units digit = a + 2
⇒ The number = 100a + 10(a + 1) + a + 2 = 111a + 12
The number formed by reversing the digits = 100(a + 2) + 10(a + 1) + a
= 111a + 210 
Since the number formed by reversing the digits exceeds the original number by 22 times, the sum of the digits
 111a + 210 - 111a - 12 = 22(a + 2 + a + 1 + a)
⇒ 
198 = 66a + 66 

 
a = 2

Hence, the required number = 111a + 12 = 111 
×
 2 + 12 = 234
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Most Upvoted Answer
A number consists of 3 consecutive digits, such that the digit in the ...
To solve this problem, let's break it down step by step:

Step 1: Understand the problem
We are given a number consisting of 3 consecutive digits, with the greatest digit in the units place. We need to find the number, given that the number formed by reversing the digits exceeds the original number by 22 times the sum of the digits.

Step 2: Let's assume the number
Let's assume the number as ABC, where A, B, and C are consecutive digits. Since the digit in the units place is the greatest, C would be the greatest digit.

Step 3: Write the original number
The original number can be written as 100A + 10B + C.

Step 4: Write the reversed number
The reversed number can be written as 100C + 10B + A.

Step 5: Write the equation
According to the problem, the reversed number exceeds the original number by 22 times the sum of the digits. So, we can write the equation as:

100C + 10B + A = 100A + 10B + C + 22(A + B + C)

Simplifying the equation, we get:

99C = 99A + 21B

Step 6: Simplify the equation further
Dividing the equation by 33, we get:

3C = 3A + 7B

Simplifying it further, we get:

C = A + 2B

Step 7: Find the possible values of A, B, and C
Since A, B, and C are consecutive digits, they can be any of the following combinations:

A = 1, B = 2, C = 3
A = 2, B = 3, C = 4
A = 3, B = 4, C = 5
A = 4, B = 5, C = 6
A = 5, B = 6, C = 7
A = 6, B = 7, C = 8
A = 7, B = 8, C = 9

Out of these combinations, only A = 2, B = 3, C = 4 satisfies the equation C = A + 2B.

Therefore, the number is 234, which is option B.
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A number consists of 3 consecutive digits, such that the digit in the units place being the greatest of the three. The number formed by reversing the digits exceeds the original number by 22 times the sum of the digit. Find the number.a)231b)234c)233d)232Correct answer is option 'B'. Can you explain this answer?
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