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The sum of the squares of three consecutive positive numbers is 365. What will the sum of numbers?
  • a)
    36
  • b)
    33
  • c)
    45
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The sum of the squares of three consecutive positive numbers is 365. W...
Problem Analysis

We are given that the sum of the squares of three consecutive positive numbers is 365. Let's assume the three consecutive numbers as x, x+1, and x+2.

Solution

We can represent the sum of the squares of these three numbers as an equation:
x^2 + (x+1)^2 + (x+2)^2 = 365

Expanding the equation:
x^2 + (x^2 + 2x + 1) + (x^2 + 4x + 4) = 365
3x^2 + 6x + 5 = 365
3x^2 + 6x - 360 = 0
Divide the equation by 3:
x^2 + 2x - 120 = 0

Factorizing the Equation

We need to factorize the quadratic equation x^2 + 2x - 120 = 0 to find the values of x.

(x + 12)(x - 10) = 0

From the equation, we have two possible values for x:
x + 12 = 0 or x - 10 = 0

If x + 12 = 0, then x = -12, which is not a positive number. Hence, we discard this solution.

If x - 10 = 0, then x = 10. This gives us the first number as 10.

Calculating the Other Numbers

Using the value of x = 10, we can calculate the other two consecutive numbers:
First number: x = 10
Second number: x + 1 = 10 + 1 = 11
Third number: x + 2 = 10 + 2 = 12

Sum of the Numbers

The sum of the three numbers is:
10 + 11 + 12 = 33

Therefore, the correct answer is option 'B', which is 33.
Free Test
Community Answer
The sum of the squares of three consecutive positive numbers is 365. W...
Suppose the three consecutive positive numbers be x, x + 1, and x + 2
According to the question,
(x)2 + (x + 1)2 + (x + 2)2 = 365
On expanding, we will get,
x2 + x2 + 1 + 2x + x2 + 4 + 4x = 365
3x2 + 6x = 360
Or, x2 + 2x - 120 = 0
=> (x - 10) (x + 12) = 0
So, x = 10
First number x = 10
Second number x + 1 = 11
Third number x + 2 = 12
So, sum of the numbers is = 10 + 11 + 12 = 33
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