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Find the number of integral values of x satisfying √(−x ^2 10x − 16 ) < x-2?="" />
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Find the number of integral values of x satisfying √(−x ^2 10x − 16 ...
Problem: Find the number of integral values of x satisfying √(−x^2 10x − 16) < />

Solution:

Step 1: Simplifying the inequality

-√(−x^2 10x − 16) < />

Squaring both sides, we get:

x^2 - 4x + 4 > -x^2 + 10x + 16

Simplifying, we get:

2x^2 - 14x - 12 < />

Dividing by 2, we get:

x^2 - 7x - 6 < />

Step 2: Factoring

We can factor the quadratic as:

(x - 1)(x - 6) < />

Step 3: Plotting the inequality

We can plot the inequality on a number line as follows:

<---o---o---o---o---o---o---o--->

-1 0 1 2 3 4 5 6 7

We need to find the values of x that satisfy the inequality (x - 1)(x - 6) < 0.="" these="" are="" the="" values="" of="" x="" that="" lie="" between="" the="" roots="" of="" the="" />

Step 4: Solving the inequality

-1 < x="" />< />

The integral values of x that satisfy the inequality are:

x = 0, 1, 2, 3, 4, 5

Answer: There are 6 integral values of x that satisfy the inequality.
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Find the number of integral values of x satisfying √(−x ^2 10x − 16 )
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