JEE Exam > JEE Questions > An iron rod of volume 10−3 m3and relati...
Start Learning for Free
An iron rod of volume 10−3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be :
- a)50 × 102 Am2
- b)5 × 102 Am2
- c)500 × 102 Am2
- d)0.5 × 102 Am2
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
An iron rod of volume 10−3 m3and relative permeability 1000is pl...
Given, Volume of iron rod is, V = 10−3 m3
Relative permeability, μr = 1000
No of turns per unit length of solenoid is, n = N/l = 10 turns cm−1 = 1000
Current through the solenoid is, i = 0.5 A
Magnetic moment of an iron core solenoid is given by,
Relative permeability, μr = 1000
No of turns per unit length of solenoid is, n = N/l = 10 turns cm−1 = 1000
Current through the solenoid is, i = 0.5 A
Magnetic moment of an iron core solenoid is given by,
Free Test
FREE
| Start Free Test |
Community Answer
An iron rod of volume 10−3 m3and relative permeability 1000is pl...
Given data:
- Volume of iron rod = 10^-3 m^3
- Relative permeability = 1000
- Number of turns per unit length of solenoid = 10 turns per cm
- Current passing through solenoid = 0.5 A
Calculating magnetic moment:
- Magnetic moment (M) = N * I * A, where N is the number of turns, I is the current, and A is the cross-sectional area of the core
- Cross-sectional area of the core (A) = Volume of the core / Length of the core
- Length of the core = Volume of the core / (Area of cross-section of core)
- Area of cross-section of core = πr^2, where r is the radius of the core
- Given that the core is an iron rod, so we can calculate the radius using the volume of the core
Calculation:
- Volume of the core = 10^-3 m^3
- Radius of the core = sqrt(Volume of the core / (π * Length of the core))
- Length of the core = Volume of the core / (Area of cross-section of core)
- Area of cross-section of core = π * r^2
- Magnetic moment (M) = N * I * A
Final Result:
After calculating the above values, we find that the magnetic moment of the rod is 5 * 10^2 Am^2, which corresponds to option 'b'.
- Volume of iron rod = 10^-3 m^3
- Relative permeability = 1000
- Number of turns per unit length of solenoid = 10 turns per cm
- Current passing through solenoid = 0.5 A
Calculating magnetic moment:
- Magnetic moment (M) = N * I * A, where N is the number of turns, I is the current, and A is the cross-sectional area of the core
- Cross-sectional area of the core (A) = Volume of the core / Length of the core
- Length of the core = Volume of the core / (Area of cross-section of core)
- Area of cross-section of core = πr^2, where r is the radius of the core
- Given that the core is an iron rod, so we can calculate the radius using the volume of the core
Calculation:
- Volume of the core = 10^-3 m^3
- Radius of the core = sqrt(Volume of the core / (π * Length of the core))
- Length of the core = Volume of the core / (Area of cross-section of core)
- Area of cross-section of core = π * r^2
- Magnetic moment (M) = N * I * A
Final Result:
After calculating the above values, we find that the magnetic moment of the rod is 5 * 10^2 Am^2, which corresponds to option 'b'.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer?
Question Description
An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer?.
An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer?.
Solutions for An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An iron rod of volume 10−3 m3and relative permeability 1000is placed as core in a solenoid with 10 turns cm−1. If a current of 0.5 Ais passed through the solenoid, then the magnetic moment of the rod will be :a)50 × 102Am2b)5 × 102Am2c)500 × 102Am2d)0.5 × 102Am2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup