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A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span
Calculate the maximum deflection by area moment method
Ans is 0.17mm?
Calculate the maximum deflection by area moment method
Ans is 0.17mm?
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A simply supported beam 5m span of cross sectional area of 40mm square...
Problem Statement: Calculate the maximum deflection of a simply supported beam of 5m span, cross-sectional area of 40mm square, second area of moment is equal to 400 × 10^6, young's modulus of elasticity is 1.2 × 10^6. The centroid of bending moment lies at 2m and it carries a UDL of 5KNm over the entire span. Solve the problem using the area moment method.
Solution:
To solve the problem the following steps are taken:
Step 1: Calculate the moment of inertia (I)
I = (b × d³) / 12
where, b = breadth of the cross-section and d = depth of the cross-section
I = (40 × 40³) / 12
I = 1.07 × 10^6 mm^4
Step 2: Calculate the maximum bending moment (M)
M = (w × L²) / 8
where, w = UDL and L = span of the beam
M = (5 × 5²) / 8
M = 15.63 KNm
Step 3: Calculate the maximum deflection (δ)
δ = (w × L⁴) / (8 × E × I)
where, E = young's modulus of elasticity
δ = (5 × 5⁴) / (8 × 1.2 × 10^6 × 1.07 × 10^6)
δ = 0.17 mm
Conclusion: The maximum deflection of the beam is 0.17 mm.
Solution:
To solve the problem the following steps are taken:
Step 1: Calculate the moment of inertia (I)
I = (b × d³) / 12
where, b = breadth of the cross-section and d = depth of the cross-section
I = (40 × 40³) / 12
I = 1.07 × 10^6 mm^4
Step 2: Calculate the maximum bending moment (M)
M = (w × L²) / 8
where, w = UDL and L = span of the beam
M = (5 × 5²) / 8
M = 15.63 KNm
Step 3: Calculate the maximum deflection (δ)
δ = (w × L⁴) / (8 × E × I)
where, E = young's modulus of elasticity
δ = (5 × 5⁴) / (8 × 1.2 × 10^6 × 1.07 × 10^6)
δ = 0.17 mm
Conclusion: The maximum deflection of the beam is 0.17 mm.
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A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm?
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A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm?.
A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam 5m span of cross sectional area of 40mm square with second area of moment is equal to 400 multiply 10 to the power 6 youngs modulus of elasticity is 1.2 multiply 10 to the power 6 the centroid of bending moment lies at 2m it carries an UDL of 5KNm over the entire span Calculate the maximum deflection by area moment methodAns is 0.17mm?.
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