Solution:
Given, sin 60°
Trigonometric ratio of 60°
Let's consider a right-angled triangle ABC where angle B=90° and angle A=60°. Let the length of side AB be 'a', side BC be 'b' and side AC be 'c'.
Now, using trigonometric ratios, we can write:
- Sin 60° = Perpendicular/Hypotenuse = AB/AC
- Cos 60° = Base/Hypotenuse = BC/AC
- Tan 60° = Perpendicular/Base = AB/BC
Calculation of the value of sin 60°
In triangle ABC, we know that angle B=90° and angle A=60°. Therefore, angle C=30° (sum of angles of a triangle is 180°).
Using the concept of trigonometric ratios, we can write:
sin 60° = AB/AC
Now, in triangle ABC:
BC = a and AC = 2a (as angle A = 60°, angle B = 90°, so angle C = 30°, which means that BC is half of AC)
Using Pythagoras theorem:
a² = (AC)² - (BC)²
a² = (2a)² - a²
3a² = 4a²
a² = 4a²/3
a = (√3/2)a
Therefore, AB = (√3/2)a and AC = 2a
sin 60° = AB/AC = (√3/2)a/2a = √3/2
Final Answer:
The value of sin 60° is √3/2.