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12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded. The composition in volume of the mixture will be
- a)0.8 litre of hydrogen and 22.4 litre of HCl
- b)24 litre of HCl
- c)22.4 litre of HCl
- d)0.8 litre of chlorine and 20.8 litre of HCl
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded...
Solution:
Given,
Volume of hydrogen = 12 L
Volume of chlorine = 11.2 L
The balanced equation for the reaction between hydrogen and chlorine is:
H2(g) + Cl2(g) → 2HCl(g)
Volume of hydrogen and chlorine are in the ratio of 1:1.
So, the limiting reagent is either hydrogen or chlorine, whichever is present in lesser amount.
So, chlorine is the limiting reagent in this case.
The amount of chlorine required to react with 12 L of hydrogen is:
1 volume of hydrogen = 1 volume of chlorine
12 volumes of hydrogen = 12 volumes of chlorine
But, only 11.2 L of chlorine is present.
So, all the chlorine will be consumed in the reaction and excess hydrogen will be left unreacted.
The amount of hydrogen left unreacted can be calculated as:
Volume of hydrogen left unreacted = Volume of hydrogen - Volume of chlorine used
= 12 L - 11.2 L
= 0.8 L
The volume of HCl formed can be calculated by using the balanced chemical equation:
1 volume of hydrogen = 1 volume of HCl
12 volumes of hydrogen = 12 volumes of HCl
So, 12 L of hydrogen will react to form 12 L of HCl.
The volume of HCl formed due to the reaction between 11.2 L of chlorine and 12 L of hydrogen is:
Volume of HCl formed = 2 × Volume of chlorine used
= 2 × 11.2 L
= 22.4 L
Therefore, the composition in volume of the mixture will be:
- 0.8 L of unreacted hydrogen
- 22.4 L of HCl formed
Hence, the correct option is (a) 0.8 litre of hydrogen and 22.4 litre of HCl.
Given,
Volume of hydrogen = 12 L
Volume of chlorine = 11.2 L
The balanced equation for the reaction between hydrogen and chlorine is:
H2(g) + Cl2(g) → 2HCl(g)
Volume of hydrogen and chlorine are in the ratio of 1:1.
So, the limiting reagent is either hydrogen or chlorine, whichever is present in lesser amount.
So, chlorine is the limiting reagent in this case.
The amount of chlorine required to react with 12 L of hydrogen is:
1 volume of hydrogen = 1 volume of chlorine
12 volumes of hydrogen = 12 volumes of chlorine
But, only 11.2 L of chlorine is present.
So, all the chlorine will be consumed in the reaction and excess hydrogen will be left unreacted.
The amount of hydrogen left unreacted can be calculated as:
Volume of hydrogen left unreacted = Volume of hydrogen - Volume of chlorine used
= 12 L - 11.2 L
= 0.8 L
The volume of HCl formed can be calculated by using the balanced chemical equation:
1 volume of hydrogen = 1 volume of HCl
12 volumes of hydrogen = 12 volumes of HCl
So, 12 L of hydrogen will react to form 12 L of HCl.
The volume of HCl formed due to the reaction between 11.2 L of chlorine and 12 L of hydrogen is:
Volume of HCl formed = 2 × Volume of chlorine used
= 2 × 11.2 L
= 22.4 L
Therefore, the composition in volume of the mixture will be:
- 0.8 L of unreacted hydrogen
- 22.4 L of HCl formed
Hence, the correct option is (a) 0.8 litre of hydrogen and 22.4 litre of HCl.
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12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded. The composition in volume of the mixture will bea)0.8 litre of hydrogen and 22.4 litre of HClb)24 litre of HClc)22.4 litre of HCld)0.8 litre of chlorine and 20.8 litre of HClCorrect answer is option 'A'. Can you explain this answer?
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12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded. The composition in volume of the mixture will bea)0.8 litre of hydrogen and 22.4 litre of HClb)24 litre of HClc)22.4 litre of HCld)0.8 litre of chlorine and 20.8 litre of HClCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded. The composition in volume of the mixture will bea)0.8 litre of hydrogen and 22.4 litre of HClb)24 litre of HClc)22.4 litre of HCld)0.8 litre of chlorine and 20.8 litre of HClCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 12 litre of hydrogen and 11.2 litre of chlorine are mixed and exploded. The composition in volume of the mixture will bea)0.8 litre of hydrogen and 22.4 litre of HClb)24 litre of HClc)22.4 litre of HCld)0.8 litre of chlorine and 20.8 litre of HClCorrect answer is option 'A'. Can you explain this answer?.
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