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What is the output of the following code?
int x = 5;
int y = 10;
int z = ++x + y--;
System.out.println(z);
int x = 5;
int y = 10;
int z = ++x + y--;
System.out.println(z);
- a)15
- b)16
- c)17
- d)Compilation Error
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
What is the output of the following code?int x = 5;int y = 10;int z = ...
The pre-increment operator (++x) increments the value of x before assigning it to the variable y. The post-decrement operator (y--) decrements the value of y after assigning it to the variable z. Therefore, the value of z will be 16.
Most Upvoted Answer
What is the output of the following code?int x = 5;int y = 10;int z = ...
The given code snippet is written in Java and it involves the use of arithmetic operators and assignment operators.
Let's break down the code and understand each step:
1. Declaring variables:
- `int x = 5;` - Here, we declare an integer variable `x` and assign it the value 5.
- `int y = 10;` - Here, we declare another integer variable `y` and assign it the value 10.
2. Evaluating expression:
- `int z = x y--;` - This line of code involves multiple operations, so let's break it down further:
- `x` - The value of `x` is 5.
- `y--` - This is a post-decrement operator. It means that the value of `y` will be used in the expression, and then it will be decremented by 1. So, the value of `y` used in this expression is 10, and after the expression, the value of `y` becomes 9.
- The expression `x y--` is equivalent to `x - y`, which is `5 - 10`.
- So, the value of `z` is `-5`.
3. Printing the result:
- `System.out.println(z);` - This line of code prints the value of `z` on the console.
- In this case, `-5` will be printed.
Hence, the correct answer is option 'B' - `-5`.
Let's break down the code and understand each step:
1. Declaring variables:
- `int x = 5;` - Here, we declare an integer variable `x` and assign it the value 5.
- `int y = 10;` - Here, we declare another integer variable `y` and assign it the value 10.
2. Evaluating expression:
- `int z = x y--;` - This line of code involves multiple operations, so let's break it down further:
- `x` - The value of `x` is 5.
- `y--` - This is a post-decrement operator. It means that the value of `y` will be used in the expression, and then it will be decremented by 1. So, the value of `y` used in this expression is 10, and after the expression, the value of `y` becomes 9.
- The expression `x y--` is equivalent to `x - y`, which is `5 - 10`.
- So, the value of `z` is `-5`.
3. Printing the result:
- `System.out.println(z);` - This line of code prints the value of `z` on the console.
- In this case, `-5` will be printed.
Hence, the correct answer is option 'B' - `-5`.
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