JEE Exam  >  JEE Questions  >  Electron emits radiation with a wavelength of... Start Learning for Free
Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.
  • a)
    4
  • b)
    3
  • c)
    5
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Electron emits radiation with a wavelength of 4900 x10-10 m from a cer...
Given:

According to the question,
We know that,

Since the radiation is in the Balmer series (Visible region)
Therefore, n1=2

Hence, this is the correct option.
Free Test
Community Answer
Electron emits radiation with a wavelength of 4900 x10-10 m from a cer...
Given Data:
- Wavelength of radiation emitted by electron: 4900 x 10^-10 m
- RH (Rydberg constant): 1.097 x 10^7 m^-1

Formula Used:
The formula to calculate the wavelength of radiation emitted in the Balmer series is given by:
1/λ = RH (1/n1^2 - 1/n2^2)

Solving the equation:
- Given wavelength = 4900 x 10^-10 m
- RH = 1.097 x 10^7 m^-1
- Let n1 = 2 (for Balmer series)
- Let n2 = n (to be determined)
Plugging in the values in the formula:
1/(4900 x 10^-10) = 1.097 x 10^7 (1/2^2 - 1/n^2)
Solving further gives:
n = 4
Therefore, the electronic state of the electron emitting radiation with a wavelength of 4900 x 10^-10 m in the Balmer series is 4. Hence, the correct answer is option 'A'.
Explore Courses for JEE exam
Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer?
Question Description
Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer?.
Solutions for Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Electron emits radiation with a wavelength of 4900 x10-10 m from a certain electronic state and is lying in the Balmer series in the spectrum of hydrogen atom. Find the electronic state of the electron. Take approximate value and RH = 1.097 x 107m-1.a)4b)3c)5d)2Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev