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A bar of length L and of uniform cross-sectional area A. and second moment of area I is subjected to a pull P. If young’s modulus of elasticity of the bar material is E, the expression for strain energy stored in the bar will be
  • a)
    P2L/2AE
  • b)
    PL2/2AE
  • c)
    PL2/AE
  • d)
    P2L/AE
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A bar of length L and of uniform cross-sectional area A. and second mo...
's modulus of the material is E, the elongation (δ) of the bar can be calculated using the following formula:

δ = PL / AE

where:

δ = elongation of the bar (m)
P = pull force applied to the bar (N)
L = length of the bar (m)
A = cross-sectional area of the bar (m^2)
E = Young's modulus of the material (Pa)

This formula assumes that the bar is linearly elastic, meaning that it will return to its original shape once the force is removed and that the force is applied along the axis of the bar. If the bar is not linearly elastic, additional factors may need to be considered.
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A bar of length L and of uniform cross-sectional area A. and second moment of area I is subjected to a pull P. If young’s modulus of elasticity of the bar material is E, the expression for strain energy stored in the bar will bea)P2L/2AEb)PL2/2AEc)PL2/AEd)P2L/AECorrect answer is option 'A'. Can you explain this answer?
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