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X on heating with soda lime gives ethane. X can be:
- a)Ethanoic acid.
- b)Methanoic acid.
- c)Propanoic acid.
- d)Ethanol.
Correct answer is option 'C'. Can you explain this answer?
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X on heating with soda lime gives ethane. X can be:a)Ethanoic acid.b)M...
The method of preparation of an alkane using soda lime (which is a mixture of NaOH and CaO) is known as soda lime decarboxylation.
In soda lime decarboxylation, carboxylic acid is heated with soda lime, resulting into the formation of alkane having one carbon less than carboxylic acid.
In soda lime decarboxylation, carboxylic acid is heated with soda lime, resulting into the formation of alkane having one carbon less than carboxylic acid.
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X on heating with soda lime gives ethane. X can be:a)Ethanoic acid.b)M...
Propanoic acid (Option C) is the correct answer.
Propanoic acid, also known as propionic acid, is a carboxylic acid with the chemical formula CH3CH2COOH. When heated with soda lime, propanoic acid undergoes decarboxylation to produce ethane.
Here's a detailed explanation:
Decarboxylation Reaction:
- Decarboxylation is a chemical reaction that involves the removal of a carboxyl group from a molecule.
- In the case of propanoic acid, heating with soda lime (a mixture of sodium hydroxide and calcium oxide) leads to the removal of the carboxyl group (-COOH) from the molecule.
- This process results in the formation of ethane (C2H6) as a product.
Reasons for Choosing Propanoic Acid:
- Ethanoic acid (Option A) and Methanoic acid (Option B) are both weaker acids compared to propanoic acid and are less likely to undergo decarboxylation under the given conditions.
- Ethanol (Option D) is an alcohol and does not contain a carboxyl group, so it cannot undergo decarboxylation to form ethane.
- Propanoic acid contains a carboxyl group which makes it suitable for decarboxylation to produce ethane when heated with soda lime.
Therefore, propanoic acid is the most appropriate choice for the given reaction conditions, yielding ethane as the final product.
Propanoic acid, also known as propionic acid, is a carboxylic acid with the chemical formula CH3CH2COOH. When heated with soda lime, propanoic acid undergoes decarboxylation to produce ethane.
Here's a detailed explanation:
Decarboxylation Reaction:
- Decarboxylation is a chemical reaction that involves the removal of a carboxyl group from a molecule.
- In the case of propanoic acid, heating with soda lime (a mixture of sodium hydroxide and calcium oxide) leads to the removal of the carboxyl group (-COOH) from the molecule.
- This process results in the formation of ethane (C2H6) as a product.
Reasons for Choosing Propanoic Acid:
- Ethanoic acid (Option A) and Methanoic acid (Option B) are both weaker acids compared to propanoic acid and are less likely to undergo decarboxylation under the given conditions.
- Ethanol (Option D) is an alcohol and does not contain a carboxyl group, so it cannot undergo decarboxylation to form ethane.
- Propanoic acid contains a carboxyl group which makes it suitable for decarboxylation to produce ethane when heated with soda lime.
Therefore, propanoic acid is the most appropriate choice for the given reaction conditions, yielding ethane as the final product.
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X on heating with soda lime gives ethane. X can be:a)Ethanoic acid.b)Methanoic acid.c)Propanoic acid.d)Ethanol.Correct answer is option 'C'. Can you explain this answer?
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